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1 answer:
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Explanation:
For the given reaction
Now, expression for half-life of a second order reaction is as follows.
....... (1)
Second half life of this reaction will be . So, expression for this will be as follows.
=
...(2)
where is the final concentration that is,
here and
is the initial concentration.
Hence, putting these values into equation (2) formula as follows.
=
= ...... (3)
Now, dividing equation (3) by equation (1) as follows.
=
= 3
or, = 3
Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.
The new volume of the balloon : V₂ = 4.89 L
<h3>Further explanation</h3>Given
V₁ = 4.96 L
T₁ = 6 + 273 = 279 K
T₂ = 2 + 273 = 275 K
Required
The new volume
Solution
Charles's Law
When the gas pressure is kept constant, the gas volume is proportional to the temperature
Input the value :
V₂=V₁.T₂/T₁
V₂ = 4.96 x 275 / 279
V₂ = 4.89 L