Ionic compounds generally occur between metals and non-metals due to their large electronegativity difference. You can simple go down Group 1 and Group 17 of the periodic table.
Examples:
NaCl (Sodium Chloride)
KCl (Potassium Chloride)
RbCl (Rubidium Chloride)
CsCl (Cesium Chloride)
Answer:
It becomes a positive ion and its radius decreases
Explanation:
As per the Octet rule, Barium has 2 electrons in its outermost shell. When it loses the two electron it gains two positive charge i.e Ba2+. As the barium loses the two electron from its outermost shell, the outermost shell becomes vacant and thus is no more considered as a part of atomic geometry of the barium atom and since the outermost shell is considered negligible the radius of barium atom reduces automatically.
Following the law of conservation of mass, the mass percent of hydrogen in the resulting compound is 14.4%(wt/wt). This is assuming that all of the carbon reacts with all of the hydrogen. The solution is as follows:
mass % = mass hydrogen*100/total mass = 28.8*100/(28.8+171.2) = 14.4%
Answer:
DeltaG0 = -(1) X 96485 X 0.034 = -3280.49 J /mole = -3.281 KJ / mole
Explanation:
E0cell = E0cathode - E0anode
the cathode will be with more reduction potential and anode will have low reduction potential
E0cell = 0.254 - 0.220 = 0.034 V
Now
DeltaG0 = -nFE0cell
E0cell = 0.034 V
F = 96485 C
n = 1
Putting values
DeltaG0 = -(1) X 96485 X 0.034 = -3280.49 J /mole = -3.281 KJ / mole