Relative atomic mass of NaCl=23+35.5=58.5
2000kg / 58.5 = mass per relative atomic mass = 34.188
34.188 * atomic mass of Na, 34.188 * 23 = 786.325... = 790 kg (2s.f.)
Answer:
Postulate: Gas particles are extremely small and are far apart.
The activities can be used to demonstrate the postulate is :
<u>Observing colored gas spreading into an inverted jar placed on top of a jar containing the gas</u>
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Explanation:
colored gas spreading into an inverted jar placed on top of a jar containing the gas:
This occur because of two reasons:
1. <em><u>The Gaseous particles are largely spaced . There is large distance between the gases molecule</u></em>
<em><u>2. The gases are in continuous motion . Hence they posses very high kinetic energy . This is the reason they mixes quickly if placed in a jar.</u></em>
<em><u>This occur by the process of diffusion. </u></em>
Diffusion of Gases: The intermixing of particles from the region of high concentration to low concentration.
The coloured gas goes into the space between the gaseous molecule present in the jar.(Gases are far apart)
As soon as the coloured gas is mixed in the jar , It spread quickly by diffusion because , The gaseous particles are extremely small and are far apart.
Mass to mass: moles A x(mole ratio of B/A) and mass to mole: extract the data from the question
Answer:
5-chloro-1,3-cyclopentadiene
Explanation:
5-chloro-1,3-cyclopentadiene will react more slowly in an SN1 reaction. ( i.e. No reaction as the product is unstable ) attached is the representation of the rate of reaction of both Halides which shows that 5-chloro-1,3-cyclopentadiene reacts the slowest .
Also During SN1 reaction Carbocation is formed .
Attached below is the solution explanation
Answer:
1.61 x 10²⁰ molecules
Explanation:
Given parameters:
Mass of the hydrogen gas = 8.01 x 10⁻⁴g
Unknown
Number of molecules of NH₃ = ?
Solution:
Given reaction:
N₂ + 3H₂ → 2NH₃
We have to solve from the known to the unknown
- The known specie is the mass of H₂ ;
find the number of moles of the specie;
number of moles = 
Molar mass of H₂ = 2(1) = 2g/mol
Number of moles = 
= 0.0004mol
- 3 moles of H₂ will produce 2 moles of NH₃
0.0004 moles of H₂ will produce 
= 0.00027moles of NH₃
1 mole of a substance contains 6.02 x 10²³ molecules
0.00027mole of NH₃ will contain 0.00027 x 6.02 x 10²³
= 1.61 x 10²⁰ molecules
