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Chemistry

2 answers:

iogann1982 [59]2 years ago

6 0

I believe it is wind

Vsevolod [243]2 years ago

4 0

Wind is the primary driving force of surface currents. The Coriolis effect deflects the currents to the right or left of their path of motion.

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Our good friend and pseudo scientist, homer simpson, attempts to analyze 300 mg of an unknown compound containing only c and h b

iragen [17]

$C_{x}H_{y} + O_{2} --\ \textgreater \ x CO_{2} + \frac{y}{2} H{2}O

540mg H_{2}O* \frac{1 mmol H_{2}O}{18 mg H_{2}O} =30 mmol H_{2}O

\\ \\30 mmolH_{2}O -have - 60 mmol H
\\ \\ 60 mmol H* \frac{1mg H}{1 mmol H} =60 mg H
\\ \\300mg C_{x}H_{y} - 60 mg H= 240 mg C
\\ \\ 240 mgC* \frac{1mmol}{12mg} =20 mmol C

20 mmol C: 60 mmol H=1 mol C : 3 mol H

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7 0

3 years ago

Particle 1 has a velocity v1 = 2 m/s and a mass m1 = 2 kg . this particle collides with particle 2 of mass m2 = 6 kg , which is

creativ13 [48]

This follows the law of conservation of momentum. Momentum is the product of mass and velocity of object.
Momentum = mass(m) x velocity(v)
law of conservation of momentum means that the total momentum of system before the collision of 2 objects is equal to the total momentum after the collision
Before the collision total momentum
= m1v1 + m2v2
m1 = 2 kg
v1 = 2 m/s
m2 = 6 kg
v2 = 0 m/s
substituting the values in the equation
total momentum before = (2 kg x 2 m/s) + (6 kg x 0 m/s)
total momentum = 4 kgm/s
after the collision the 2 objects stick together and have a common velocity
total momentum after the collision = (6 kg + 2 kg)x V = 8V
V = speed of the conglomerate particle

since total momentum before is equal to total momentum after
8V = 4
V = 2 m/s
speed of conglomerate particle is 2 m/s

8 0

2 years ago

Please select the word from the list that best fits the definition

leonid [27]

Answer:

Systemic Circulation

Explanation:

7 0

2 years ago

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A small amount of acid is added to a buffer solution, the ph of the solution will

Alik [6]