Please help me to solve the problem<br>?cm=1m

Suppose your salary in 2012 is $70,000. Assuming an annual inflation rate of 7%, what salary do you need to earn in 2020 in orde

s2008m [1.1K]

Annual salary(2012) = $70,000

Annual inflation = 7%

Therefore, the salary you need to earn in 2020 in order to have the same purchasing power can be calculated below

$2020-2012=8\text{ years}$ $FV=PV\times(1+r)^n$

where

n = 8

r = 7/100 = 0.07

PV = 70, 000

$\begin{gathered} FV=70,000(1+0.07)^8 \\ FV=70000(1.07)^8 \\ FV\text{ = 70000}\times1.71818617983 \\ FV=120273.032588 \\ FV=\text{ \$}120,273.03 \end{gathered}$

The salary you need to earn in 2020 to have the same purchasing power = $120, 273.03

8 0

1 year ago

Find the period of the leg of a man who is 1.83 m in height with a mass of 67 kg. The moment of inertia of a cylinder rotating a

In-s [12.5K]

Answer:

$T = 1.108\,s$

Explanation:

The period of a physical pendulum is:

$T = \sqrt{\frac{I_{O}}{m\cdot g \cdot L} }$

$T=2\cdot \pi \sqrt{\frac{\frac{1}{3}\cdot m \cdot L^{2} }{m\cdot g\cdot L} }$

$T=2\cdot \pi \sqrt{\frac{L }{3\cdot g} }$

The length of the leg is approximately the height of the person:

$L = 0.915\,m$

The period is:

$T = 2\cdot \pi \sqrt{\frac{0.915\,m}{3\cdot (9.807\,\frac{m}{s^{2}} )} }$

$T = 1.108\,s$

4 0

3 years ago

Calculate the gravitational attraction between two objects which masses are: mass A: 2.5kg, mass B: 5kg. The distance between th

jonny [76]

From the calculation, the gravitational force of attraction is 1.33 * 10^-14 N.

<h3>What is the gravitational force?</h3>

The gravitational force is an attractive force that acts between any two masses.

It is given by;

F = Gm1m2/r^2

F = 6.67 * × 10−11 * 2.5 * 5/(250)^2

F = 83.4 × 10−11 /62500

F= 1.33 * 10^-14 N

Learn more about gravitational force:brainly.com/question/12528243

#SPJ1

4 0

2 years ago

Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at

netineya [11]

Answer:

Δu=1300kJ/kg

Explanation:

Energy at the initial state

$p_{1}=200kPa\\t_{1}=300^{o}\\u_{1}=2808.8kJ/kg(tableA-5)$

Is saturated vapor at initial pressure we have

$p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)$

Process 2-3 is a constant volume process

$p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)$

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

$=2808.8kJ/kg-1508.6kJ/kg\\=1300kJ/kg$

Δu=1300kJ/kg

3 0

3 years ago

A 100kg bag of sand has a weight on 100 N. When dropped it's acceleration is what?

Vesnalui [34]

Answer:

9.8m/s

Explanation:

acceleration due to gravity is independent of mass

7 0

2 years ago

Please help me to solve the problem?cm=1m​

Please help me to solve the problem?cm=1m