Steam enters a cylinder—- A
Answer:
293k
Explanation:
In this question, we are asked to calculate the temperature to which the reaction must be heated to double the equilibrium constant.
To find this value, we will need to use the Van’t Hoff equation.
Please check attachment for complete solution
The magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.
Speed of the proton = 5.02 × 10 ⁶ m /a
Angel of between the velocity and the magnetic force = 60 °
The magnitude of magnetic field B = 0.180 T
The magnitude of the magnetic force on the proton is,




Therefore, the magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.
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Answer:
4.88 m/s
Explanation:
Vertical component would be 12 * sin 24 = 4.88 m/s
Horizontal is 12 * cos 24