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aalyn [17]
3 years ago
8

Which number is larger value : 5.6*10^23 or 8.9*10^6 Need Help

Physics
1 answer:
oee [108]3 years ago
8 0

Answer:

5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps

Explanation:

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Como se encuentra <br><br> el agua a una temperatura menor de 0ºC
Rudiy27

Answer:

yes

Explanation:

Yes, water can stay liquid below zero degrees Celsius. There are a few ways in which this can happen.

6 0
3 years ago
If a spring stores 5 j of energy when its compressed by 0.5 m. what is the spring constant
aliya0001 [1]

The elastic potential energy stored in a spring is given by:

E=\frac{1}{2}kx^2

where k is the spring constant, and x=0.5 is the compression of the spring. Re-arranging the formula and using E=5 J, we find the spring constant:

k=\frac{2E}{x^2}=\frac{2(5 J)}{(0.5 m)^2}=40 N/m

3 0
3 years ago
Read 2 more answers
What's the kinetic energy of an object that has a mass of 30 kilograms and moves with a velocity of 20m/s?
icang [17]

Ek = 6KJ.

In physics, the kinetic energy of a body or object is the one that owns due to its movement and is given by the equation E_{k} = \frac{1}{2} mv^{2}, where m is the mass of the object in kilograms and v is the velocity in m/s.

An object that it has a mass of 30 kilograms and moves with a velocity of 20m/s, its kinetic energy is given by:

E_{k} = \frac{1}{2} (30kg)(20m/s)^{2}=6000J=6KJ

4 0
3 years ago
The cable of a crane is lifting a 750 kg girder. The girder increases its speed from 0.25 m/s to 0.75 m/s in a distance of 3.5 m
IgorC [24]

To solve this exercise it is necessary to apply the equations concerning Work, both by general definition and by conservation of energy.

In other words, the work done by an object due to gravity is the equivalent to that defined by the potential energy equations, that is

W= mg\Delta h

Where,

m=mass

g=gravitational acceleration

\Delta h = Change in height

On the other hand we have that the work done by tension is defined by the conservation of kinetic and potential energy, that is to say

W= \Delta KE + \Delta PE

Where,

\Delta KE = Change in Kinetic Energy

\Delta PE =Change in Potential Energy

PART A) As defined by the work done by gravity would be given by,

W = mg\Delta h

W = (750)(9.8)(3.5)

W = 25.725kJ

Therefore the work done by gravity is 25.725kJ

PART B) The work done by the tension applies the energy conservation equation, that is to say

W= \Delta KE + \Delta PE

W = (\frac{1}{2}mv_f^2-\frac{1}{2}mv_i^2)+(mgh_f-mgh_i)

W = \frac{1}{2}m(v_f^2-v_i^2)+mg(h_f-h_i)

Replacing with our values,

W = \frac{1}{2}(750)(0.75^2-0.25^2)+(750)(9.8)(3.5)

W = 25.912kJ

Therefore the work done by tension is 25.9kJ

5 0
4 years ago
How much heat is required to convert 50 g of ice at -5 degrees Celsius to steam?
12345 [234]

Answer:

15435 J

Explanation:

Latent heat of fusion, Lf = 334 J/g

Specific heat of ice, ci = 2.1 J / g C

Latent heat of vaporisation, Lv = 2230 J/g

Specific heat of water, cw = 4.18 J / g C

mass, m = 50 g, T = - 5 degree C

There are following steps

(i) - 5 degree C ice converts into 0 degree C ice

H1 = m x ci x ΔT = 50 x 2.1 x 5 = 525 J

(ii) 0 degree C ice converts into 0 degree C water

H2 = m x Lf = 5 x 334 = 1670 J

(iii) 0 degree C water converts into 100 degree C water

H3 = m x cw x ΔT = 5 x 4.18 x 100 = 2090 J

(iv) 100 degree C water converts into 100 degree C steam

H4 = m x Lv = 5 x 2230 = 11150 J

Total heat required

H = H1 + H2 + H3 + H4

H = 525 + 1670 + 2090 + 11150 = 15435 J

3 0
3 years ago
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