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2 years ago

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Which number is larger value : 5.610^23 or 8.910^6 Need Help

1 answer:

oee [108]2 years ago

8 0

Answer:

5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps

Explanation:

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In a given circuit, the supplied voltage is 1.5 volts. One resistor is 3 ohms and the other is 2 ohms. Use Ohm's law to determin

ozzi

You haven't said whether the two resistors are connected
in series or in parallel. It makes a difference.

-- If they are in series, then their combined effective resistance is

(3 + 2) = 5 ohms.

Current in the circuit is (voltage)/(resistance) = 1.5/5 = 0.3 Amp.

-- If they are in parallel, then their combined effective resistance is

(3 x 2) / (3 + 2) = (6/5) = 1.2 ohms.

Current in the circuit is (voltage)/(resistance) = 1.5/1.2 = 1.25 Amp.

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Fossils found in the La Brea tar pits indicate a California climate that was A) similar to today's climate. B) similar to the pr

NikAS [45]

Answer:

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Explanation:

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3 years ago

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Write the equation for eccentricity

Svetradugi [14.3K]

<span>e=ca{\displaystyle e={\frac {c}{a}}}.</span>

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3 years ago

A driver averaged 64 mph and took 3½ hours to travel from st. Louis to chicago. Based on this, what is the distance between st.

sammy [17]

Average speed of the driver is given as

$v = 64 mph$

if he moved for total time t = 3.5 hours

so the distance between the tow is given as

$d = v* t$

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3 years ago

Suzy drops a rock from the roof of her house. Mary sees the rock pass her 2.9 m tall window in 0.134 sec. From how high above th

timama [110]

Answer:

Explanation:

Given

length of window $h=2.9\ m$

time Frame for which rock can be seen is $\Delta t=0.134\ s$

Suppose h is height above which rock is dropped

Time taken to cover $h+2.9 is t_1$

so using equation of motion

$y=ut+\frac{1}{2}at^2$

where y=displacement

u=initial velocity

a=acceleration

t=time

time taken to travel h is

$h=0+0.5\times g\times (t_2)^2---2$

Subtract 1 and 2 we get

$2.9=0.5g(t_1^2-t_2^2)$

$5.8=g(t_1+t_2)(t_1-t_2))$

and from equation $t_1-t_2=0.134\ s$

so $t_1+t_2=\frac{5.8}{9.8\times 0.134}$

$t_1+t_2=4.416\ s$

and $t_1=t_2+\Delta t$

so $t_2+\Delta t+t_2=4.416$

$2t_2+0.134=4.416$

$t_2=0.5\times 4.282$

$t_2=2.141\ s$

substitute the value of $t_2$ in equation 2

$h=0.5\times 9.8\times (2.141)^2$

$h=22.46\ m$

8 0

3 years ago