How much work in J does the string do on the boy if the boy stands still?
<span>answer: None. The equation for work is W = force x distance. Since the boy isn't moving, the distance is zero. Anything times zero is zero </span>
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<span>How much work does the string do on the boy if the boy walks a horizontal distance of 11m away from the kite? </span>
<span>answer: might be a trick question since his direction away from the kite and his velocity weren't noted. Perhaps he just set the string down and walked away 11m from the kite. If he did this, it is the same as the first one...no work was done by the sting on the boy. </span>
<span>If he did walk backwards with no velocity indicated, and held the string and it stayed at 30 deg the answer would be: </span>
<span>4.5N + (boys negative acceleration * mass) = total force1 </span>
<span>work = total force1 x 11 meters </span>
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<span>How much work does the string do on the boy if the boy walks a horizontal distance of 11m toward the kite? </span>
<span>answer: same as above only reversed: </span>
<span>4.5N - (boys negative acceleration * mass) = total force2 </span>
<span>work = total force2 x 11 meters</span>
Translate please, i’d be able to help better:)
Answer:
When the starting and ending points are the same, the total work is zero.
Explanation:
option ( D )correct
A force is said to be conservative when the work done by the force in moving a particle from a point A to a point B is independent of the path followed between A and B and is the same for all the paths. The work done depends only on the particles initial and final positions. And when the initial and final position in conservative field are same the work done is said to be zero.
The tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.
<h3>Principle of moments</h3>
The Principle of Moments states that when a body is in equip, the sum of clockwise moment about a point is equal to the sum of anticlockwise moment about the same point.
The formula for calculating moment is given below:
- Moment = Force × perpendicular distance from the pivot
<h3>Calculating the tension in the chains</h3>
From the principle of moments:
Let tension in chain 1 be T1 and tension in chain 2 be T2.
T1 + T2 = 150 + 650 + 419
T1 + T2 =1219
Taking all distances from chain 1,
Sum of Moments = 0
419 × 0.5 + 150 × 0.85 + 650 × 0.9 = T2 × 1.7
T2 = 922/17
T2 = 542.35 N
Then, T1 = 1219 - 542.35
T1 = 676.65 N
Therefore, the tension in the two chains T1 and T2 is 676.65 N and 542.53 N respectively.
Learn more about tension and moments at: brainly.com/question/187404
brainly.com/question/14303536
Answer:
Obviously the answer is Sun...
