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3 years ago

2.

Physics

1 answer:

horrorfan [7]3 years ago

6 0

Answer:

B. 6HgO → 6Hg + 3O $_{2}$

Explanation:

A decomposition reaction is a reaction in which a single reactant is broken down into 2 or more products.

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Can somebody please help with these

Sever21 [200]

Answer:

Fusion

Fission

Explanation:

The first problem describes a nuclear fusion process. In this process;

small atomic nuclei combines to form a larger one.
it is accompanied by a large release of energy
this energy provides the needed temperature to set up another light nuclei to fuse.

The second problem describes nuclear fission,

a heavy nuclide is bombarded with a neutron.
the product formed becomes unstable and subsequently breaks down.
This leads to a series of chain reactions until stability is attained.

6 0

3 years ago

Why am i getting so many spam calls on my cell phone.

OleMash [197]

Answer:

Why do I keep getting spam calls? Experts credit the ascendance of spam phone calls to fundamental problems with caller ID, a phone system where anyone can operate as a carrier, the inability to detect bad callers, and a number of bad actors exploiting those flaws to drive billions of calls to American phones.

Explanation:

5 0

2 years ago

An observer in frame S sees lightning simultaneously strike two points 100 m apart. The first strike occurs at xx1 = yy1 = zz1 =

Veseljchak [2.6K]

Answer:

a) 0, = -0.33 us

b) 140m

c) No, The event are not simultaneous i.e they did not occur at the same time, the second even (-0.33 usec) occurs 0.33 usec earlier than the first event.

Explanation:

the lorentz factor expression is written as;

y = 1₀ / √(1 - (v²/c²))

where v is the relative speed of an observer and c is the speed of light

so we were given that relative speed to be o.7c

therefore

y = 1 / √(1 - ((0.7c)² / c²))

y = 1 / √(1 - (0.49c² / c²))

y = 1 / √(1 - 0.49)

y = 1 / 0.7141

y = 1.4

1 - the coordinates of the first event, the s' frame of reference is,

x1 ' = y(x1 - vt1) = 0

y1 ' = y1, z1' = z1 and

t1 ' = y [t1 - v/c²x1]

= 0

2 - the coordinates of the second event, the s ' frame of reference is'

x2 ' = y(x2-vt2)

= 1.4(100m - 0)

= 140m

y2 ' = y2, z2 ' = z2

t2 ' = y [ t2 - v/c²x2 ]

= 1.4 [ 0 - 0.7c/c²(100) ]

using speed of light c as 3*10^8

1.4 [ 0 - (0.7*3*10^8) / (3*10^8)²(100) ]

= -0.33 us

distance between

delltaX' = X2' - X1'

= 140m - 0

= 140m

No, The event are not simultaneous i.e they did not occur at the same time.

the second even (-0.33 us) occurs 0.33 us earlier than the first event.

4 0

3 years ago

A 5.0 kg chunk of putty moving at 10m/s collides and sticks to a 7.0 kg bowling ball that is initially at rest.What is the total

Flura [38]

Answer:

Total momentum = 50kgm/s

Explanation:

Given the following data;

Mass, M1 = 5kg

Mass, M2 = 7kg

Velocity, V1 = 10m/s

Velocity, V2 = 0m/s (since it's at rest).

To find the total momentum;

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

$Momentum = Mass * Velocity$

The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

Total momentum = M1V1 + M2V2

Substituting into the equation, we have;

Total momentum = 5*10 + 7*0

Total momentum = 50 + 0

Total momentum = 50 kgm/s

Therefore, the total momentum of the bowling ball and the putty after they collide is 50 kgm/s.

8 0

3 years ago

A car with a velocity of 30 mph

Leokris [45]

Answer:

First calculate the deceleration making use of the formulation: V(very last speed= U(initial speed) -a(acceleration) t(ime) so 10=20- 4a. unfavourable a as decelerating. making a the acceleration the challenge by using rearranging the elements 4a= 20-10 = 10 so a=10/4 making use of Newton's 2d regulation P(stress) = M (mass) x A (acceleration). so P = 800 x 10/4 = 8000 /4 = 2000 newtons

Explanation:

4 0

3 years ago