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pochemuha
3 years ago
12

2.

Physics
1 answer:
horrorfan [7]3 years ago
6 0

Answer:

B. 6HgO → 6Hg + 3O_{2}

Explanation:

A decomposition reaction is a reaction in which a single reactant is broken down into 2 or more products.

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Convert 400 mm to m using the method of dimensional analysis
s2008m [1.1K]

Answer:

To convert 400 mm to m you can apply the formula [m] = [mm] / 1000; use 400 for mm. Thus, the conversion 400 mm m is the result of dividing 400 by 1000. 0.4

<em>PLEASE</em><em> </em><em>MARK</em><em> </em><em>AS</em><em> </em><em>BRAINLIEST</em><em> </em><em>ANSWER</em><em> </em>

7 0
2 years ago
What is the eccentricity of an ellipse with a foci distance of 50,000,000 km and
inysia [295]

Answer:

25,000,000 Km ;)

Explanation:

5 0
3 years ago
Una ola oceánica viaja a aproximadamente 1,97 m / s. Esto es 4 millas por hora. La frecuencia de las ondas es de aproximadamente
yKpoI14uk [10]

Answer:

λ = 28,14 m

Explanation:

To find the wavelength of the wave you use the following formula:

v=\lambda f  (1)

v: speed of the wave = 1,97 m/s

λ: wavelength

f: frequency of the wave = 0,07 Hz

You replace the values of v and f in the equation (1) and solve for λ:

\lambda=\frac{v}{f}=\frac{1,97m/s}{0,07Hz}=28,14m

hence, the wavelength of the wave is 28,14 m

5 0
3 years ago
A space station in the shape of a 100 m-diameter (50m radius) wheel is spinning so as to impart a linear tangential speed of 22.
zalisa [80]

Answer:

correct option is b. 31.3 m/s

Explanation:

given data

artificial gravity a1 = 1 g

artificial gravity a2 = 2 g

diameter = 100 m

radius  r= 50 m

speed v1 = 22.1 m/s

solution

As acceleration is  ∝ v²

so we can say

\frac{a2}{a1} = \frac{v2}{v1}    .....................1

put here value

\frac{2}{1} = \frac{v2}{22.1}  

solve it

v2 = \sqrt{2 } × 22.1

v2 = 31.25 m/s

so correct option is b. 31.3 m/s

4 0
3 years ago
A painter stands a horizontal platform which has a mass of 20kg and is 5m long, the platform is suspended by two vertical ropes
Lerok [7]

Answer:

R = 715.4 N

L =  166.6 N

Explanation:

ASSUME the painter is standing right of center

Let L be the left rope tension

Let R be the right rope tension

Sum moments about the left end to zero. Assume CCW moment is positive

R[5] - 20(9.8)[5/2] - 70(9.8)[5/2 + 2] = 0

R = 715.4 N

Sum moments about the right end to zero

20(9.8)[5/2] + 70(9.8)[5/2 - 2] - L[5] = 0

L =  166.6 N

We can verify by summing vertical forces

116.6 + 715.4 - (70 + 20)(9.8) ?=? 0

                                             0 = 0  checks

If the assumption about which side of center the paint stood is incorrect, the only difference would be the values of L and R would be swapped.

5 0
3 years ago
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