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Ksju [112]
3 years ago
6

A teacher stands well back from an outside doorway 0.88 m wide, and blows a whistle of frequency 780 Hz. Ignoring reflections, e

stimate at what angle(s) it is not possible to hear the whistle clearly on the playground outside the doorway.
Physics
1 answer:
AlladinOne [14]3 years ago
5 0

the wavelength is to be 56.67 cm and I know that i should be applying the double slit equation for destructive interference.

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Which of the following correctly describes the formula for speed?
Aleksandr [31]
Option C is the right answer
6 0
3 years ago
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In t-ball, young players use a bat to hit a stationary ball off a stand. The 140 g ball has about the same mass as a baseball, b
fomenos

Question is missing. Found on google:

<em>"Part A What is the acceleration of the ball? Express your answer to two significant figures and include the appropriate units. </em>

<em>Part B </em>

<em>What is the net force on the ball during the hit?  </em>

<em>Express your answer to two significant figures and include the appropriate units."</em>

Solution:

A) 6000 m/s^2

The acceleration of the ball is given by

a=\frac{v-u}{t}

where

v = 12 m/s is the final velocity

u = 0 is the initial velocity (the ball is stationary)

t = 2.0 ms = 0.002 s is the time of contact

Substituting,

a=\frac{12-0}{0.002}=6.0 \cdot 10^3 m/s^2

B) 8.4\cdot 10^2 N

The force on the ball can be found by using Newton's second law:

F=ma

where

m = 140 g = 0.14 kg is the mass of the ball

a=6.0\cdot 10^3 m/s^2 is the acceleration

Substituting,

F=(0.14)(6.0\cdot 10^3)=8.4\cdot 10^2 N

3 0
3 years ago
the SI and CGS unit of force are newton and dyne respectively haow many dynes are equal to one newton​
Triss [41]

Answer:

For example, the CGS unit of force is the dyne, which is defined as 1 g⋅cm/s2, so the SI unit of force, the newton (1 kg⋅m/s2), is equal to 100000 dynes.

Explanation:

5 0
3 years ago
The repulsive force between two protons has a magnitude of 2.00 N. What is the distance between them?
Aloiza [94]

Answer:

The answer to your question is letter A.     r = 1.07 x 10⁻¹⁴ m

Explanation:

Data

F = 2 N

d = ?

q = 1.6 x 10 ⁻¹⁹ C

k = 8.987 Nm²/C²

Formula

                 F = K\frac{q1q2}{r^{2}}

Solve for r

                r = \sqrt{\frac{kq1q2}{F}}

Substitution

                r = \sqrt{\frac{8.987 x 10^{9}x1.6 x 10^{-19} x 1.6 x 10x^{-19}}{2}}

Simplification

                r = \sqrt{\frac{2.3 x 10^{-28}}{2}}

                r = \sqrt{1.15 x 10^{-24}}

Result

                r = 1.07 x 10⁻¹⁴ m

6 0
3 years ago
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Identify Label these cell parts
Kruka [31]

Answer:

I don't know this answer because I am not American

8 0
3 years ago
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