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Misha Larkins [42]
2 years ago
11

A roller coaster with a potential energy of 235,200 J sits at the top of a 30 m high hill. What is the mass of the roller

Physics
2 answers:
xxTIMURxx [149]2 years ago
5 0

Answer:

800 kg

Explanation:

I just did it :)

igomit [66]2 years ago
4 0

Answer:

the correct answer is A. 800 kg

Explanation:

i got the answer right on the quiz, i hope this helps!

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One of the most efficient heat engines ever built is a coal-fired steam turbine in the Ohio River valley, operating between 1 87
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Answer:The answer

Explanation:

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3 years ago
Susan's 12.0 kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30∘ above the
Pavlova-9 [17]

Answer:1.71 m/s

Explanation:

Given

mass of Susan m=12 kg

Inclination \theta =30^{\circ}

Tension T=29 N

coefficient of Friction \mu =0.18

Resolving Forces Along x axis

F_x=T\cos \theta -f_r

where f_r=friction\ Force  

F_y=mg-N-T\sin \theta

since there is no movement in Y direction therefore

N=mg-T\sin \theta

and f_r=\mu N

Thus F_x=T\cos \theta -\mu N

F_x=29\cos (30)-\0.18\times (12\times 9.8-29\sin (30))                

F_x=25.114-18.558

F_x=6.556 N

Work done by applied Force is equal to change to kinetic Energy

F_x\cdot x=\frac{1}{2}\cdot mv_f^2-\frac{1}{2}\cdot mv_i^2

6.556\times 2.7=\frac{1}{2}\cdot 12\times v_f^2

v_f^2=\frac{6.556\times 2.7\times 2}{12}

v_f^2=2.95

v_f=1.717 m/s        

8 0
3 years ago
2 decaliters + 800 deciliters = __________ liters?
Stolb23 [73]
Answer is 100 liters
8 0
3 years ago
Read 2 more answers
How do you calculate average speed?
Mila [183]

Divide
       (the distance covered in some period of time)
by
       (the time taken to cover the distance).

The quotient is the average speed during that period of time.
4 0
3 years ago
Read 2 more answers
Consider horizontal parallel plates with a fixed potential difference. The upper plate has a voltage difference of 30 V with the
BlackZzzverrR [31]

relation between potential difference and electric field is given as

E . d = \Delta V

so here we know that

d = 3 cm

\Delta V = 30 V

E \times 0.03 = 30

E = 1000 N/C

So now when plates are separated to 4 cm distance carefully

the potential difference between them will change but the electric field between them will remain constant

So at distance of 4 cm also the electric field will be E = 1000 N/C

5 0
3 years ago
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