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Hoochie [10]
1 year ago
13

Correctly label the following structures surrounding the small intestine. Stomach Appendix lleum Cecum Jejunum Ascending colon

Physics
1 answer:
kifflom [539]1 year ago
7 0

The structures that are surrounding the small intestine in the image are: stomach, ascending colon, cecum and appendix.

<h3>What is the small intestine?</h3>

The small intestine will be part of the digestive system and it is the smallest part of the intestine, it will be after the stomach and before the ascending colon. It will be made up of three parts: duodenum, which is the one attached to the stomach, ileum, and jejunum.

Each of its parts is going to have certain specific functions related to digestion, absorption and have immunity as a function.

Among the characteristics of the small intestine, absorption stands out since its surface is created for better absorption, since it will have circular folds, intestinal villi and microvilli. These will increase the absorption surface, so it works better.

To learn more about small intestine visit: brainly.com/question/24180887

#SPJ1

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Explanation:

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I which types of galaxy are globular clusters most likely to be found?
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3 years ago
If 2 objects had the same momentum, what must be true about the mass of the object that traveled the fastest?
julsineya [31]

Yes, the above-given statement is true

<u>Explanation:</u>

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3 years ago
Heat transfers energy from a hot object to a cold object. Both objects are isolated from their surroundings. The change in entro
aniked [119]

To develop this problem we will start from the definition of entropy as a function of total heat, temperature. This definition is mathematically described as

S = \frac{Q}{T}

Here,

Q = Total Heat

T = Temperature

The total change of entropy from a cold object to a hot object is given by the relationship,

\Delta S = \frac{Q}{T_{cold}}-\frac{Q}{T_{hot}}

From this relationship we can realize that the change in entropy by the second law of thermodynamics will be positive. Therefore the temperature in the hot body will be higher than that of the cold body, this implies that this term will be smaller than the first, and in other words it would imply that the magnitude of the entropy 'of the hot body' will always be less than the entropy 'cold body'

Change in entropy \Delta S_{hot} is smaller than \Delta S_{cold}

Therefore the correct answer is C. Will always have a smaller magnitude than the change in entropy of the cold object

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Answer:

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