Question

The energy required to ionize magnesium is 738 kj/mol. What minimum frequency of light is required to ionize magnesium

Answer 1

Answer:

The minimum frequency required to ionize the photon is 111.31 × $10^{37}$ Hertz

Given:

Energy = 378 $\frac{kJ}{mol}$

To find:

Minimum frequency of light required to ionize magnesium = ?

Formula used:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

Solution:

The energy of photon of light is given by,

E = h v

Where E = Energy of magnesium

h = planks constant

v = minimum frequency of photon

738 × $10^{3}$ = 6.63 × $10^{-34}$ × v

v = 111.31 × $10^{37}$ Hertz

The minimum frequency required to ionize the photon is 111.31 × $10^{37}$ Hertz

Answer 2

Explanation:

Relation between energy and frequency is as follows.

                     E = $h \nu$

where,   E = energy

              h = planck's constant = $6.626 \times 10^{-34}$ Js

          $\nu$ = frequency

As it is given that value of energy is 738 kJ/mol.

          E = $\frac{738 \times 1000 J}{6.022 \times 10^{23}}$

             = $1.22 \times 10^{-18}$ J

Hence, putting the given values into the above formula as follows.

                      E = $h \nu$

    $1.22 \times 10^{-18}$ J = $6.626 \times 10^{-34} Js \times \nu$  

                    $\nu$ = $1.84 \times 10^{15}$ per second

Thus, we can conclude that $1.84 \times 10^{15}$ per second is the minimum frequency of light which is required to ionize magnesium.