Answer:
0.96 m
Explanation:
First, convert km/h to m/s.
162.3 km/h × (1000 m/km) × (1 hr / 3600 s) = 45.08 m/s
Now find the time it takes to move 20 m horizontally.
Δx = v₀ t + ½ at²
20 m = (45.08 m/s) t + ½ (0 m/s²) t²
t = 0.4436 s
Finally, find how far the ball falls in that time.
Δy = v₀ t + ½ at²
Δy = (0 m/s) (0.4436 s) + ½ (-9.8 m/s²) (0.4436 s)²
Δy = -0.96 m
The ball will have fallen 0.96 meters.
The pictures are not attached, therefore, I cannot give a specific choice.
However, I will try to help you out.
The angle of incidence is defined as the angle formed between the ray of light and the normal to the surface that the ray is falling on.
The angle of incidence can be shown in the attached image.
Therefore, for your question, choose the image on which the above description applies.
Hope this helps :)
Answer:
- Time delta is associated with difference in wavelengths
Explanation:
When pulsating radio waves consisting of different wavelengths pass through the ionized gas in interstellar space, the fast oscillating radio waves travel relatively faster than the slowly oscillating radio waves. As a result radio waves get dispersed and there is a time difference between the radio waves with different wavelength when the pulses arrive.
The change in speed of this object is 3m/s
According to Newton's second law;
F = ma
F = mv/t
Given the following parameters
Force F = 8.0N
mass m = 16kg
time t = 4.0s
Required
speed v
Substitute the given parameters into the formula
v = Ft/m
v = 8 * 6/16
v = 48/16
v = 3m/s
Hence the change in speed of this object is 3m/s
Learn more here: brainly.com/question/19072061
Answer:
C. Why you must push harder to move a car farther.
Explanation:
Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.
Mathematically, it is given by the formula;
Hence, Newton's 2nd Law explains why you must push harder to move a car farther because of its mass. Thus, it is important to increase the force that the engine provides and decrease the mass of the car.