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Fudgin [204]
2 years ago
11

wishing to collect weather data on a remote island, you come up with an idea for sending a weather balloon to the location. You

attach a +1 C charged object to the balloon and plan to propel the balloon to the island using an electrostatic force. Given the balloon's size and standard wind patterns en route, you realize you will need to be able to overcome an opposing air resistance of up to 100N at any point on the balloon's 750km journey to the island. How big oof a charge will you need at your location to propel the +1C balloon, even in the face if the opposing wind, up to a distance of 750 km away?
Physics
1 answer:
gtnhenbr [62]2 years ago
4 0

The magnitude of the second charge needed to propel the first charge is 6,250 C.

<h3>Magnitude of the second charge to propel the first charge</h3>

The magnitude of the second charge is calculated by applying Coulomb's law as follows;

F = kq₁q₂/r²

where;

  • k is Coulomb's constant
  • q₁ is magnitude of first charge
  • q₂ is magnitude of second charge
  • r is the distance between the charges

Fr² =  kq₁q₂

q₂ = Fr²/kq₁

q₂ = (100 x 750,000²)/(9 x 10⁹ x 1)

q₂ = 6,250 C

Thus, the magnitude of the second charge needed to propel the first charge is 6,250 C.

Learn more about charges here: brainly.com/question/18102056

#SPJ1

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A grapefruit falls from a tree and hits the ground 0.72 s later.
xxTIMURxx [149]

Answer:

<em>The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s</em>

Explanation:

<u>Free Fall Motion </u>

A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is g = 9.8 m/s^2.

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

\displaystyle y=\frac{gt^2}{2}

Given a grapefruit free falls from a tree and hits the ground t=0.72 s later, we can calculate the height it fell from:

\displaystyle y=\frac{9.8\cdot 0.72^2}{2}

y = 2.54 m

The final speed is computed below:

vf=9.8\cdot 0.72

vf = 7.06 m/s

The grapefruit dropped 2.54 m and hit the ground at 7.06 m/s

6 0
3 years ago
Finding the spring constant as shown, spring 3, which has an unknown spring constant k3, replaces spring 2. the mass of the weig
nevsk [136]
Replaces spring 2. the mass of the weight and pulley are unchanged: m=5.8 kg and mp=1.7 kg
6 0
4 years ago
. A newly discovered planet has three times the mass and five times the radius of Earth. What is the ratio of the acceleration d
NikAS [45]

Answer:

0.12

Explanation:

The acceleration due to gravity of a planet with mass M and radius R is given as:

g = (G*M) / R²

Where G is gravitational constant.

The mass of the planet M = 3 times the mass of earth = 3 * 5.972 * 10^24 kg

The radius of the planet R = 5 times the radius of earth = 5 * 6.371 * 10^6 m

Therefore:

g(planet) = (6.67 * 10^(-11) * 3 * 5.972 * 10^24) / (5 * 6.371 * 10^6)²

g(planet) = 1.18 m/s²

Therefore ratio of acceleration due to gravity on the surface of the planet, g(planet) to acceleration due to gravity on the surface of the planet, g(earth) is:

g(planet)/g(earth) = 1.18/9.8 = 0.12

3 0
3 years ago
Air pressure increases as you travel higher above sea level. This is the reason that cabins in commercial airliners require pres
irakobra [83]

The answer is true about the cabins in commercial airliners that require pressurization.

<h3>Why are the cabins of commercial airplanes pressurized?</h3>

Airplanes are pressurized because the air is very thin at the high altitude where they fly. The passenger jet has a cruising altitude of about 30,000 - 40,000 feet. At this altitude or height, humans can't breathe very well and our body gets less amount of oxygen. Most aircraft cabins are pressurized to an altitude about 8,000 feet. This is called cabin altitude. Aircraft pilots have access to the control's mode of a cabin pressure control system and if needed it can command the cabin to depressurize.

So we can conclude that cabins in commercial airliners require pressurization because of the greater pressure of the surrounding environment.

Learn more about pressure here: brainly.com/question/28012687

#SPJ1

4 0
1 year ago
A charge of −8.3 μC is traveling at a speed of 7.4 × 106 m/s in a region of space where there is a magnetic field. The angle bet
solniwko [45]

Answer:

The magnitude of the magnetic field is   1.1\times 10^{-4}\, T

Explanation:

Given charge q = −8.3 μC

speed of charge v=7.4\times 10^{6}\, \frac{m}{s}

Angle between magnetic field and the velocity of charge \Theta =52^{\circ}

Strength of magnetic force on charge F=5.4\times 10^{6}\, N

Let magnitude of magnetic field be B

Since the magnetic force on a free moving charge in the magnetic field given by

F=\left |q\vec{v}\times \vec{B}\right |=\left | qvBsin\Theta\right |

=>5.4\times 10^{-3}=\left | -8.3\times 10^{-6}\times 7.4\times 10^{6}\times sin(52^{\circ})\times B \right |

=>B=1.1\times 10^{-4}\, T

Thus the magnitude of the magnetic field is   1.1\times 10^{-4}\, T

4 0
3 years ago
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