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Fudgin [204]
2 years ago
11

wishing to collect weather data on a remote island, you come up with an idea for sending a weather balloon to the location. You

attach a +1 C charged object to the balloon and plan to propel the balloon to the island using an electrostatic force. Given the balloon's size and standard wind patterns en route, you realize you will need to be able to overcome an opposing air resistance of up to 100N at any point on the balloon's 750km journey to the island. How big oof a charge will you need at your location to propel the +1C balloon, even in the face if the opposing wind, up to a distance of 750 km away?
Physics
1 answer:
gtnhenbr [62]2 years ago
4 0

The magnitude of the second charge needed to propel the first charge is 6,250 C.

<h3>Magnitude of the second charge to propel the first charge</h3>

The magnitude of the second charge is calculated by applying Coulomb's law as follows;

F = kq₁q₂/r²

where;

  • k is Coulomb's constant
  • q₁ is magnitude of first charge
  • q₂ is magnitude of second charge
  • r is the distance between the charges

Fr² =  kq₁q₂

q₂ = Fr²/kq₁

q₂ = (100 x 750,000²)/(9 x 10⁹ x 1)

q₂ = 6,250 C

Thus, the magnitude of the second charge needed to propel the first charge is 6,250 C.

Learn more about charges here: brainly.com/question/18102056

#SPJ1

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Ymorist [56]

Answer:

5.3×10⁴ m/s

Explanation:

From the question,

Momentum = mass× velocity

M = mV................ Equation 1

Where M = momentum of the airplane, m = mass of the airplane, V = Velocity of the airplane

make V the subject of the equation

V = M/m.................. Equation 2

Given: M = 1.6×10⁹ Kg.m/s, m = 3.0×10⁴ kg

Substitute these values into equation 2

V = 1.6×10⁹/3.0×10⁴

V = 5.3×10⁴ m/s

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3 years ago
Calcula el valor de la velocidad de las ondas sonoras en el agua sabiendo que su
dybincka [34]
  1. La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.
  2. La longitud de onda de las ondas sonoras es 1,470 metros.

1) Inicialmente, debemos determinar la velocidad de las ondas sonoras a través del agua (v), en metros por segundo:

v = \sqrt{\frac{K}{\rho} } (1)

Donde:

  • K - Módulo de compresibilidad, en newtons por metro cuadrado.
  • \rho - Densidad del agua, en kilogramos por metro cúbico.

Si sabemos que \rho = 1\times 10^{3}\,\frac{kg}{m^{3}} y K = 2,16\times 10^{9}\,\frac{N}{m^{2}}, entonces la velocidad de las ondas sonoras es:

v = \sqrt{\frac{2,16\times 10^{9}\,\frac{N}{m^{2}}}{1\times 10^{3}\,\frac{kg}{m^{3}} } }

v\approx 1469,694\,\frac{m}{s}

La velocidad de las ondas sonoras es aproximadamente 1469,694 metros por segundo.

2) Luego, determinamos la longitud de onda (\lambda), en metros, mediante la siguiente fórmula:

\lambda = \frac{v}{f} (2)

Donde f es la frecuencia de las ondas sonoras, en hertz.

Si sabemos que v\approx 1469,694\,\frac{m}{s} y f = 1000\,hz, entonces la longitud de onda de las ondas sonoras es:

\lambda = \frac{1469,694\,\frac{m}{s} }{1000\,hz}

\lambda = 1,470\,m

La longitud de onda de las ondas sonoras es 1,470 metros.

Para aprender más sobre las ondas sonoras, invitamos a ver esta pregunta verificada: brainly.com/question/1070238

6 0
2 years ago
Which of these is an uneven rhythm movement? Question 5 options:
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Answer:

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Explanation:

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This had to do with gain power and trade inequality business
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The fundamental frequency of a standing wave on a 1.0-m-long string is 440 Hz. What would be the wave speed of a pulse moving al
Nana76 [90]

Answer: v = 880m/s

Explanation: The length of a string is related to the wavelength of sound passing through the string at the fundamental frequency is given as

L = λ/2 where L = length of string and λ = wavelength.

But L = 1m

1 = λ/2

λ = 2m.

But the frequency at fundamental is 440Hz and

V = fλ

Hence

v = 440 * 2

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4 0
3 years ago
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