1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fudgin [204]
2 years ago
11

wishing to collect weather data on a remote island, you come up with an idea for sending a weather balloon to the location. You

attach a +1 C charged object to the balloon and plan to propel the balloon to the island using an electrostatic force. Given the balloon's size and standard wind patterns en route, you realize you will need to be able to overcome an opposing air resistance of up to 100N at any point on the balloon's 750km journey to the island. How big oof a charge will you need at your location to propel the +1C balloon, even in the face if the opposing wind, up to a distance of 750 km away?
Physics
1 answer:
gtnhenbr [62]2 years ago
4 0

The magnitude of the second charge needed to propel the first charge is 6,250 C.

<h3>Magnitude of the second charge to propel the first charge</h3>

The magnitude of the second charge is calculated by applying Coulomb's law as follows;

F = kq₁q₂/r²

where;

  • k is Coulomb's constant
  • q₁ is magnitude of first charge
  • q₂ is magnitude of second charge
  • r is the distance between the charges

Fr² =  kq₁q₂

q₂ = Fr²/kq₁

q₂ = (100 x 750,000²)/(9 x 10⁹ x 1)

q₂ = 6,250 C

Thus, the magnitude of the second charge needed to propel the first charge is 6,250 C.

Learn more about charges here: brainly.com/question/18102056

#SPJ1

You might be interested in
Two 10-cm-diameter charged rings face each other, 25.0cm apart. Both rings are charged to +20.0nC. What is the electric field st
Black_prince [1.1K]

Answer:

Part A:

E_{midpoint}=0

Part B:

E_{center}=2711.7558 N/C

Explanation:

Part A:

Formula of Electric Field Strength:

E=\frac{1}{4\pi\epsilon}\frac{xQ}{(x^2+R^2)^{3/2}}

Where:

x is the distance from the ring

R is the radius of the ring

\epsilon is constant permittivity of free space=8.854*10^-12 farads/meter

Q is the charge

For right Ring E at the midpoint can be calculated as:

x for right plate=25/2=12.5 cm=0.125 m

Radius=R=10/2=5 cm=0.05 m

E_{right}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.125)*(20*10^{-19})}{((0.125)^2+(0.05)^2)^{3/2}}\\E_{right}=9208.1758 N/C

For Left Ring E at the midpoint can be calculated as:

Since charge on both plates is +ve and same in magnitude, the electric field will be same for both plates.

E_{left}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.125)*(20*10^{-19})}{((0.125)^2+(0.05)^2)^{3/2}}\\E_{left}=9208.1758 N/C

Electric Field at midpoint:

Both rings have same magnitude but the direction of fields will be opposite as they have same charge on them.

E_{midpoint}=E_{left}-E_{right}\\E_{midpoint}=9208.1758-9208.1758\\E_{midpoint}=0

Part B:

At center of left ring:

Due to left ring Electric field at center is zero because x=0.

E_{left}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0)*(20*10^{-19})}{((0)^2+(0.05)^2)^{3/2}}\\E_{left}=0 N/C

Due to right ring Electric field at center of left ring:

Now: x=25 cm= o.25 m (To the center of left ring)

E_{right}=\frac{1}{4\pi8.854*10^{-12}}\frac{(0.25)*(20*10^{-19})}{((0.25)^2+(0.05)^2)^{3/2}}\\E_{right}=2711.7558 N/C

Electric Field Strength at center of left ring is same as that of right ring.

E_{center}=2711.7558 N/C

5 0
3 years ago
The interference of two sound waves of slightly different frequencies produces
Leviafan [203]
Beats.

When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - a phenomenon which is called "beating" or producing beats. The beat frequency is equal to the absolute value of the difference in frequency of the two waves.
4 0
2 years ago
Read 2 more answers
Help! I don’t really know what it’s asking
Misha Larkins [42]
You have to do the math of each and see which one adds up to 66.5
6 0
2 years ago
Pls help meh! im in 5 grd<br><br> what is used to see white light?<br><br> pls respond asap!
FinnZ [79.3K]
L<span>ight with a spectral composition that stimulates all three types of the color sensitive </span>cone cells<span> of the </span>human eye<span> in nearly equal amounts appears white.





</span>
7 0
2 years ago
What is the target heart rate a female age 32
Airida [17]

Answer:

The normal resting heart rate for adults over the age of 10 years, including older adults, is between 60 and 100 beats per minute (bpm). Highly trained athletes may have a resting heart rate below 60 bpm, sometimes reaching 40 bpm. The resting heart rate can vary within this normal range.

Explanation:

I hope that answers your question!

5 0
3 years ago
Read 2 more answers
Other questions:
  • How long is a football field?
    14·2 answers
  • A completely inelastic collision occurs between two balls of wet putty that move directly toward each other along a vertical axi
    13·1 answer
  • Why are very high temperatures and pressures required for fusion to occur?
    15·1 answer
  • If the same net force is applied to a 7 kg object and a 21 kg object, then the 21 kg object accelerates three times faster than
    15·1 answer
  • A passenger jet flies from one airport to another 1293 miles away in 2.1hours . Find average speed
    11·1 answer
  • The video shows an animated billiards experiment in which a cue ball strikes a glued-in-place eight-ball. which of the following
    5·1 answer
  • The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0.46. The weight of the object
    10·1 answer
  • Same diagram... At which location would it be possible for a LUNAR ECLIPSE to happen? *
    6·2 answers
  • This is my last assignment plz help
    6·2 answers
  • Which refers to a material that causes a wave to bounce off of it?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!