Explanation:
The given data is as follows.
Angular velocity (
) = 2.23 rps
Distance from the center (R) = 0.379 m
First, we will convert revolutions per second into radian per second as follows.
= 2.23 revolutions per second
= 
= 14.01 rad/s
Now, tangential speed will be calculated as follows.
Tangential speed, v = 
= 0.379 x 14.01
= 5.31 m/s
Thus, we can conclude that the tack's tangential speed is 5.31 m/s.
Answer:
the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
Explanation:
Given the data in the question;
Kinetic energy of each proton that makes up the beam = 3.25 × 10⁻¹⁵ J
Mass of proton = 1.673 × 10⁻²⁷ kg
Charge of proton = 1.602 × 10⁻¹⁹ C
distance d = 2 m
we know that
Kinetic Energy = Charge of proton × Potential difference ΔV
so
Potential difference ΔV = Kinetic Energy / Charge of proton
we substitute
Potential difference ΔV = ( 3.25 × 10⁻¹⁵ ) / ( 1.602 × 10⁻¹⁹ )
Potential difference ΔV = 20287.14 V
Now, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m will be;
E = Potential difference ΔV / distance d
we substitute
E = 20287.14 V / 2 m
E = 10143.57 V/m or 1.01 × 10⁴ V/m
Therefore, the magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 10143.57 V/m or 1.01 × 10⁴ V/m
The final temperature of the block is 
Explanation:
The amount of thermal energy Q supplied to a substance is related to the increase in temperature of the substance, 
, according to the equation
where:
m is the mass of the substance
is the specific heat capacity of the substance
In this problem, we have:
m = 1.2 kg is the mass of the block
is the amount of energy supplied to the block
is the specific heat capacity of the block
Solving for , we find the increase in temperature:
And since the initial temperature was
The final temperature will be
Learn more about specific heat capacity:
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If the refractive index of some substance is 1.33, then
the speed of light in that substance is
(speed of light in vacuum) / (1.33) =
(299,792,458 m/s) / (1.33) = <em>225,407,863 m/s</em>
