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3 years ago

How many milligrams in 1 gram. ??? HELP !!!

Physics

2 answers:

NARA [144]3 years ago

8 0

1,000 milligrams = 1

blagie [28]3 years ago

3 0

1,000 milligrams = 1 gram
2,000 milligrams = 2 grams
3,000 milligrams = 3 grams
4,000 milligrams = 4 grams

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Which statement about thermal energy (or heat energy) is most accurate?

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It increases with the motion of particles within a substance

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3 years ago

______is the rate of change in velocity.

shepuryov [24]

Answer:

Acceleration

Explanation:

Acceleration is the rate of change in velocity

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3 years ago

A zero-order reaction has a constant rate of 2.30×10−4 M/s. If after 80.0 seconds the concentration has dropped to 1.50×10−2 M,

dolphi86 [110]

Answer:

Initial concentration of the reactant = 3.34 × 10^(-2)M

Explanation:

Rate of reaction = 2.30×10−4 M/s,

Time of reaction = 80s

Final concentration = 1.50×10−2 M

Initial concentration = Rate of reaction × Time of reaction + Final concentration

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Initial concentration = 3.34 × 10^(-2)M

6 0

3 years ago

A bucket of water of mass 14.0 kg is suspended by a rope wrapped around a windlass, that is a solid cylinder with diameter 0.260

ruslelena [56]

Answer:

The tension in the rope is 41.38 N.

Explanation:

Given that,

Mass of bucket of water = 14.0 kg

Diameter of cylinder = 0.260 m

Mass of cylinder = 12.1 kg

Distance = 10.7 m

Suppose we need to find that,

What is the tension in the rope while the bucket is falling

We need to calculate the acceleration

Using relation of torque

$\tau=F\times r$

$I\times\alpha=F\times r$

Where, I = moment of inertia

$\alpha$ = angular acceleration

$\dfrac{Mr^2}{2}\times\dfrac{a}{r}=F\times r$

$F=\dfrac{M}{2}a$ ...(I)

Here, F = tension

The force is

$F=m(g-a)$ ...(II)

Where, F = tension

a = acceleration

From equation (I) and (II)

$\dfrac{M}{2}a=m(g-a)$

$a=\dfrac{g}{1+\dfrac{M}{2m}}$

Put the value into the formula

$a=\dfrac{9.8}{1+\dfrac{12.1}{2\times14.0}}$

$a=6.84\ m/s^2$

We need to calculate the tension in the rope

Using equation (I)

$F=\dfrac{M}{2}a$

Put the value into the formula

$F=\dfrac{12.1}{2}\times6.84$

$F=41.38\ N$

Hence, The tension in the rope is 41.38 N.

6 0

3 years ago

The greatest ocean depths on earth are found in the Marianas Trench near the Philippines, where the depth of the bottom of the t

kompoz [17]

Answer:

103063860 Pa

Explanation:

$\rho$ = Density of seawater = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth at which pressure is being measured = 10.2 km

The gauge pressure is given by

$p=\rho gh\\\Rightarrow p=1030\times 9.81\times 10.2\times 10^3\\\Rightarrow p=103063860\ Pa$

Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa

3 0

3 years ago