Answer:
Induced emf in the coil,  
Explanation:
Given that.
Number of turns in the coil, N = 200
Side of square, d = 18 cm = 0.18 m
The field changes linearly from 0 to 0.50 T in 0.80 s.
To find,
The magnitude of the induced emf in the coil while the field is changing.
Solution,
We know that due to change in the magnetic field, an emf gets induced in the coil. The formula of induced emf is given by :
 
 = magnetic flux
 = magnetic flux
 
A is the ares of square
 
 
 
 
So, the induced emf in the coil is 4.05 volts. Hence, this is the required solution.
 
        
             
        
        
        
Answer:
a) 25.5 µH
b) 22.95 mV
Explanation:
Induced emf in a inductor is given by
E = L * di/dt, where 
E is the voltage of the circuit
L is the inductance of the circuit
di/dt if the rate of inductance 
A
So we have
0.0037 = L * 145
L = 0.0037 / 145
L = 0.0000255
L = 25.5 µH
B
i(t) = 225t²
Recall that
E = L * di/dt, so that
E = 25.5 µH * |225t²|
Differentiating with respect to t, we have
E = 25.5 * 2 * 225t
E = 25.5 * 450t
Solving for t = 2,we get
E = 25.5 * 450(2)
E = 25.5 * 900
E = 22950 µV or
E = 22.95 mV
 
        
             
        
        
        
The answer would be a=5 m/s^2
I hope this helps you, have a great day!
        
                    
             
        
        
        
Answer:
Explanation:
By multiplying the rotational frequency with the circumference we can determine the average speed of the object. The circular velocity formula is expressed as, vc = 2 πr / T. Where in, r denotes the radius of the circular orbit. T is time period.
 
        
                    
             
        
        
        
Answer:
 β = 114 db
Explanation:
The intensity of sound in decibles is
           β = 10 log 
in most cases Io is the hearing threshold 1 10-12 W / cm²
let's calculate the intensity of each instrument
             I / I₀ = 10 (β / 10)
             I = I₀ 10 (β / 10)
trumpet
             I1 = 1 10⁻¹² 10 (94/10)
             I1 = 2.51 10⁻³ / cm²
Thrombus
            I2 = 1 10⁻¹² 10 (107/10)
            I2 = 5.01 10-2 W / cm²
low
            I3 =1 1-12    (113/10) W/cm²
             I3 = 1,995 10-1 W / cm²
when we place the three instruments together their sounds reinforce
            I_total = I₁ + I₂ + I₃
            I_ttoal = 2.51 10-3 + 5.01 10-2 + 1.995 10-1
            I_total = 0.00251 + 0.0501 + 0.1995
            I_total = 0.25211 W / cm²
let's bring this amount to the SI system
          β = 10 log (0.25211 / 1 10⁻¹²)
            β = 114 db