solution:
The quoted atomic mass on the Periodic Table is the WEIGHTED average of the individual isotopic masses. The higher the isotopic percentage, the MORE that isotope will contribute to the isotopic mass. For this reason, most masses that are quoted on the Table are non-integral.
By way of example we could look to the hydrogen atom. The VAST majority of hydrogen atoms (in this universe) are the protium isotope. i.e. 1H, whose nuclei contain JUST the defining proton. There is a smaller percentage (>1%) of hydrogen atoms WITH one NEUTRON in their nuclei to give the deuterium isotope. i.e. 2H, and because this is relatively cheap, and easily incorporated into a molecule, deuterium labelling is routinely used in analysis.
And there is even a smaller percentage of hydrogen atoms with TWO NEUTRONS in their nuclei, to give the tritium isotope. i.e. 3H. The weighted average of the isotopic percentages gives 
Answer:
Explanation:
Given
485 L
Required
Determine the measurement not equal to 485L
<em>From standard unit of conversion;</em>
1 KL = 1000 L
<em>Multiply both sides by 485</em>
<em>Divide both sides by 1000</em>
---- This is equivalent
---------------------------------------------------------------------------------------------
<em>From standard unit of conversion;</em>
1000 mL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
Hence; is not equivalent to 485L
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<em>From standard unit of conversion;</em>
100 cL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
---- This is equivalent
---------------------------------------------------------------------------------------------
μL
<em>From standard unit of conversion;</em>
1000000 μL = 1 L
<em>Multiply both sides by 485</em>
Convert to standard form
---- This is equivalent
From the list of given options;
is not equivalent to 485L
The electron configuration of lithium atom is:
![Li:[He]2s^1](https://tex.z-dn.net/?f=Li%3A%5BHe%5D2s%5E1)
The number "2" is the value of the principal quantum number "n". Letter "s" is associated with the value of secondary quantum number "l" and it is equal to zero. The value of "m" (or magnetic quantum number) is zero too. The quantum number set for the highest energy electron will be (2, 0, 0, 1/2).
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