Which two statements are true about the wave shown?

A -3.00 nC point charge is at the origin, and a second -5.50 nC point charge is on the x-axis at x = 0.800 m.

elena-s [515]

Answer:

a) -537 N/C , b) - 327.8 N/C and c) 723.7 N/C

Explanation:

The electric field is a vector magnitude, so we must add them as vectors. The electric field equation is

E = k q / r²

Where k is the Coulomb constant that you are worth 8.99 10⁹ N m²/C², that the magnitude of the load and r the distance between the load and the test load

Let's find the field created by each charge at the point x = 0.200 m

charge 1.

This charge is at the origin, the distance is

x₁ = 0.200 m

q₁ = 3 nC = 3 10-9 C

E1 = k q₁ / x₁²

E1 = 8.99 10⁹ 3 10⁻⁹ / 0.2²

E1 = 674.25 N / C

Charge 2

This load is the point a = 0.800 m, so the distance to the test charge at 0.200 m

x₂ = 0.800 - 0.200

x₂ = 0.600 m

q₂ = -5.5 nC = -5.5 10-9 C

E2 = 8.99 10⁹ 5.5 10⁻⁹ / 0.600²

E2 = 137.35 N / C

We already have the value of each field, add them vectorially, remember that if the charges are of the same sign they repel and if they are of the opposite sign they attract, the field E1 is directed to the left and the field E2 is directed to the right

Et = -E1 + E2

Et = -674.25 + 137.25

Et = -537 N / C

The field is headed to the left

b) we perform the same procedure for another distance value

Charge 1

x = 1.20

E1 = 8.99 10⁹ 3 10⁻⁹ / 1.2²

E1 = 18.73 N / C

Chage 2

x = 0.8 - 1.2 = -0.4 m

E2 = 8.99 10⁹ 5.5 10⁻⁹ / 0.4²

E2 = 309.03 N / C

Total field, E1 is on the left and E2 goes on the left

Et = -E1 -E2

Et = -18.73 - 309.03

Et = - 327.8 N / C

The field is headed to the left

c) point at x = -0.200 m

charge 1

x = -0.200 m

E1 = 8.99 10⁹ 3 -10⁻⁹ / (-0.2)²

E1 = 674.25 N / C

charge 2

x = 0.800 - (-0.2) = 1,000 m

E2 = 8.99 10⁹ 5.5 10⁻⁹ / 1²

E2 = 49.45 N / C

Ei goes to the right and E2 goes to the right

Et = E1 + E2

Et = 674.25 +49.45

Et = 723.7 N / C

The field is headed to the right

8 0

3 years ago

Where is the strongest force coming from on scissors

Lelechka [254]

Answer:

the handle

Explanation:

7 0

2 years ago

A dragster with a mass of 700 kg attains a speed of 120 m/s in the quarter mile. Immediately after passing the timing lights, th

Bumek [7]

Answer:

The time taken is 5.55 seconds

Explanation:

Density, p = 1kg/m³

Mass of vehicle, m = 700kg

Initial speed, u = 120m/s

Area of drag chute, A = 7.5 m²

Drag coefficient, Cd = 1.4

Final velocity, v = 20m/s

time taken to decelerate to 20m/s, t = ?

EF = ma

Since the force taken into consideration is the drag force due to the drag chute,

EF = -Fd = -(pACdv²)/2 = ma

a = dv/dt

So the equation can be written as,

-(pACdv²)/2 = m dv/dt

Taking integral of the left hand side with respect to dt and the right with respect to dv with boundaries of 0 to t and u to v,

(pACd)t/2m = (1/v) - (1/u)

t = (2m/pACd) x ( (1/v) - (1/u) ) = f(V)

At V = v

t = (2 x 700)/(1)(7.5)(1.4) x (1/20) - (1/120)

t = 5.55 seconds

6 0

4 years ago

What is the velocity of a wave that has a frequency of 400 Hz and a wavelength of 0.5 meters?

fiasKO [112]

Answer:

4.2

Explanation:

8 0

3 years ago

Suppose a 65.5 kg gymnast climbs a rope. What is the tension in the rope if she climbs at a constant speed

natali 33 [55]

The tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Given:

Mass of gymnast, m = 65.5 kg

The speed 'v' of gymnast is constant

Solution:

Consider the free-body diagram of the system as shown below.

Balancing forces along the vertical axis we get:

ΣFy = 0

Thus, we get:

F = ma - (1)

where, m is mass of gymnast

a is acceleration of gymnast (a = 0m/s², as the speed is constant)

Also,

F = T - mg -(2)

where, T is tension in the rope

g is acceleration due to gravity

Equating (1) & (2), we get:

ma = T - mg

Re-arranging the equation, we get:

T = m(a+g)

Applying values in above equation we get:

T = (65.5 kg)(0 m/s²+9.8 m/s²)

T = 641.9 N

Therefore, the tension in the rope when the gymnast climbs it at constant speed is 641.9 N.

Learn more about tension here:

<u>brainly.com/question/14294135</u>

#SPJ4

7 0

2 years ago