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Tasya [4]
3 years ago
12

Help me on this science question.

Chemistry
1 answer:
mel-nik [20]3 years ago
6 0
The answer is Amarillo
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1.40 m3 is how many mL
Zarrin [17]

\LARGE{ \boxed{ \rm{ \pink{Solution:}}}}

We know, 1 m³ of space can hold 1000 l of the substance.

⇛ 1 m³ = 1000 l----(1)

And, 1 l is 1000 times more than 1 ml

⇛ 1 l = 1000 ml------(2)

So, From (1) and (2),

⇛ 1 m³ = 1000 × 1000 ml

⇛ 1m³ = 1000000 ml

We had to find,

⇛ 1.40 m³ = 1.40 × 1000000 ml

⇛ 1.40 m³ = 140/100 × 1000000 ml

⇛ 1.40 m³ = 1400000 ml

⇛ 1.40 m³ = 14,00,000 ml / 14 × 10⁵ ml / 1.4 × 10⁶ ml

☃️ <u>So</u><u>,</u><u> </u><u>1.40</u><u> </u><u>m</u><u>³</u><u> </u><u>=</u><u> </u><u>1</u><u>4</u><u> </u><u>×</u><u> </u><u>1</u><u>0</u><u>⁵</u><u> </u><u>m</u><u>l</u><u> </u><u>/</u><u> </u><u>1.4</u><u> </u><u>×</u><u> </u><u>10</u><u>⁶</u><u> </u><u>ml</u><u>.</u>

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0
3 years ago
Read 2 more answers
Why are being flammable and combustible considered to be chemical properties and not physical properties?
g100num [7]

Answer:

C. They change the substance into another substance.

Explanation:

Hope it helps!!

6 0
3 years ago
FeO+HNO3➡<br>Chemistry reaction
Ludmilka [50]
Iron(II) oxide react with nitric acid to produce iron(III) nitrate, nitrogen dioxide and water. Chemical reaction<span>. Balancing </span>chemical<span> equations.</span>
5 0
3 years ago
How many oxygen atoms are there in 5 molecules of Al2(SO4)?
timama [110]

Answer:

There are two aluminum ions and three sulfate ions; or two aluminum, three sulfur, and twelve oxygen atoms.

Explanation:

4 0
3 years ago
Select the correct answer. An adult human lung has a volume of 2. 9 liters. If its volume decreases to 1. 2 liters and it contai
maria [59]

Moles are the ratio of the mass and the molar mass of the substance given and is estimated in mol. The moles that the lungs contain when it is full is 0.12 moles.

<h3>What is the relation of the volume and moles?</h3>

Moles of the substances are directly proportional to the volume of the substance and can be shown as,

\rm \dfrac{V_{1}}{V_{2}}= \dfrac{n_{1}}{n_{2}}

Here,

Initial volume \rm (V_{1}) = 2.9 L

Final volume \rm (V_{2}) = 1.2 L

Initial moles = \rm n_{1}

Final moles \rm (n_{2}) = 0.049 mol

Substituting values in the equation:

\begin{aligned} \dfrac{2.9}{1.2} &=\rm \dfrac{n_{1}}{0.049}\\\\&= \dfrac{2.9\times 0.049}{1.2}\\\\&= 0.12\;\rm mol\end{aligned}

Therefore, the number of moles in the lungs are 0.12 moles.

Learn more about moles and volumes here:

brainly.com/question/13909347

6 0
3 years ago
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