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3 years ago

Does anybody know the answer to this?

Chemistry

1 answer:

kondor19780726 [428]3 years ago

6 0

Answer:

The answer is Conduction.

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The molar mass of monopotassium phosphate is 136.09 g/mol. How many moles of monopotassium phosphate are needed to make 250.0 ml

WINSTONCH [101]

Answer:

0.0375 moles

Explanation:

Given that:

Molar mass of monopotassium phosphate = 136.09 g/mol

Given that volume = 250.0 mL

Also,

$1\ mL=10^{-3}\ L$

So, Volume = 250 / 1000 L = 0.25 L

Molarity = 0.15 M

Considering:

$Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}$

$0.15=\frac{Moles\ of\ solute}{0.25}$

<u>Thus, moles of monopotassium phosphate needed = 0.0375 moles</u>

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3 years ago

When a person ingests alcohol which organ metabolizes most of the absorbed alcohol

almond37 [142]

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3 years ago

A 11.0 mLmL sample of 0.30 MHBrMHBr solution is titrated with 0.16 MNaOHMNaOH. Part A What volume of NaOHNaOH is required to rea

cupoosta [38]

Answer:

21 mL of NaOH is required.

Explanation:

Balanced reaction: $HBr+NaOH\rightarrow NaBr+H_{2}O$

Number of moles of HBr in 11.0 mL of 0.30 M HBr solution

= $(\frac{0.30}{1000}\times 11.0)$ moles = 0.0033 moles

Let's say V mL of 0.16 M NaOH solution is required to reach equivalence point.

So, number of moles of NaOH in V mL of 0.16 M NaOH solution

= $(\frac{0.16}{1000}\times V)$ moles = 0.00016V moles

According to balanced equation-

1 mol of HBr is neutralized by 1 mol of NaOH

So, 0.0033 moles of HBr are neutralized by 0.0033 moles of NaOH

Hence, $0.00016V=0.0033$

$\Rightarrow V=\frac{0.0033}{0.00016}=21$

So, 21 mL of NaOH is required.

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3 years ago

. If you constructed graphs, what trends do they indicate in your data?

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Answer:

A linear pattern is a continuous decrease or increase in numbers over time. On a graph, this data appears as a straight line angled diagonally up or down (the angle may be steep or shallow). So the trend either can be upward or downward.

Explanation:

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2 years ago