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2 years ago

What is the frequency of a wave that passes a given point 412 times in 4.0

Physics

2 answers:

spin [16.1K]2 years ago

4 0

Answer: A.0,0097s

Mas a unidade aí deveria ser Hertz (Hz)

Explanation:

NemiM [27]2 years ago

4 0

Answer:

103 hz

Explanation:

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What role does induction play when lightning strikes earth?

Dominik [7]

The role lightning plays in earth is when the earth is charged with positive protons, the lightning is the electron.

7 0

3 years ago

A ___ is the unit of measurement for force.

bogdanovich [222]

Answer:

Newton (N)

Explanation:

A newton is the unit of measurement for force

4 0

2 years ago

A CD has to rotate under the readout-laser with a constant linear velocity of 1.25 m/s. If the laser is at a position 3.7 cm fro

Savatey [412]

Answer:N=322.53 rpm

Explanation:

Given

Linear velocity (v)=1.25 m/s

Position from center is 3.7 cm

we know

$v=\omega \times r$

$1.25\times 100=\omega \times 3.7$

$\omega =\frac{125}{3.7}=33.78$

and $\frac{2\pi N}{60}=\omega$

$N=\frac{\omega \times 60}{2\pi }$

$N=\frac{33.78\times 60}{2\pi }$

N=322.53 rpm

8 0

3 years ago

Cynthia forgot to put the fabric softener in the wash. As her socks tumbled in the dryer, they became charged. If a small piece

polet [3.4K]

Answer:

E = 24000 N/C = 24 KN/C

Explanation:

The electric field experienced by a test charge is given by the following formula:

$E = \frac{F}{q}\\\\$

where,

E = Electric Field = ?

F = Force of attraction = 3 x 10⁻⁶ N

q = Charge on piece of lint = 1.25 x 10⁻¹⁰ C

Therefore, using these values in the equation, we get:

$E = \frac{3\ x\ 10^{-6}\ N}{1.25\ x\ ^{-10}\ C}\\\\$

6 0

2 years ago

Prove the correctness of this equation s=vt + 1/2at

Kaylis [27]

Answer:

The formula is dimensionally correct.

Explanation:

Given

$s = ut + \frac{1}{2}at^2$

Required

Prove its correctness

Write out the dimension of each:

$s = M^0LT^0$ --- displacement

$ut = M^0LT^{-1} * T$ --- velocity * time

$\frac{1}{2}at^2 = M^0LT^{-2} * T^2$ --- acceleration * square of time

The expression becomes:

$s = ut + \frac{1}{2}at^2$

$M^0LT^0 = M^0LT^{-1} * T + M^0LT^{-2} * T^2$

Apply law of indices

$M^0LT^0 = M^0LT^{-1+1} + M^0LT^{-2+2}$

$M^0LT^0 = M^0LT^{0} + M^0LT^{0}$

$M^0LT^0 = M^0LT^{0}$

Both sides of the equation are equal

5 0

2 years ago