Answer:
A box of donuts would cost: b = 3.84 + 0.18f
First, we have to find the total cost of the donuts.
12 x 0.32 = 3.84
Next, we need to determine the cost of the box. However, we don't know the surface area, just the cost per foot. We can multiply the number of square feet of the box by $0.18 to find the cost.
So our equation could be: b = 3.84 + 0.18f (where f is the surface area of the box in square feet)Explanation:
So, the force of gravity that the asteroid and the planet have on each other approximately
<h3>Introduction</h3>
Hi ! Now, I will help to discuss about the gravitational force between two objects. We already know that <u>gravitational force occurs when two or more objects interact with each other at a certain distance and generally orbit each other to their center of mass</u>. For the gravitational force between two objects, it can be calculated using the following formula :
With the following condition :
- F = gravitational force (N)
- G = gravity constant ≈ N.m²/kg²
- = mass of the first object (kg)
- = mass of the second object (kg)
- r = distance between two objects (m)
<h3>Problem Solving</h3>
We know that :
- G = gravity constant ≈ N.m²/kg²
- = mass of the first object = kg.
- = mass of the second object = kg.
- r = distance between two objects =
What was asked :
- F = gravitational force = ... N
Step by step :
<h3>Conclusion</h3>
So, the force of gravity that the asteroid and the planet have on each other approximately
<h3>See More</h3>
Gravity is a thing has depends on ... brainly.com/question/26485200
Answer:
2.5 kg/m³
Explanation:
Absolute pressure = gauge pressure + atmospheric pressure
P = Pg + Pa
The gauge pressure caused by the weight of a fluid is called the static pressure. It is equal to the density of the fluid × acceleration due to gravity × depth of the fluid,
Pg = ρgh
Therefore:
P = ρgh + Pa
300 Pa = ρ (10 m/s²) (8.00 m) + 100 Pa
ρ = 2.5 kg/m³
Answer:
f = - 20 cm
Explanation:
This exercise asks us for the focal length, which for a lens in air is
1 / f = (n₂-n₁) (1 / R₁ - 1 / R₂)
where n₂ is the refractive index of the material, n₁ is the refractive index of the medium surrounding the lens, R₁ and R₂ are the radii of the two surfaces.
In this exercise the medium that surrounds the lens is air n₁ = 1 and the lens material has an index of refraction n₂ = n = 1.50, let's substitute in the expression
- 1/40 = (n-1) (1 / R₁ -1 / R₂)
(1 / R₁ - 1 / R₂) = - 1/40 (n-1)
let's calculate
(1 / R₁ -1 / R₂) = - 1/40 (1.50 -1)
(1 / R₁ -1 / R₂) = -1/20
Now we change the construction material for one with refractive index
n = 2, keeping the radii,
1 / f = (n-1) (1 / R₁-1 / R₂)
1 / f = (n-1) (-1/20)
let's calculate
1 / f = (2.00-1) (-1/20)
1 / f = -1/20
f = - 20 cm