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OleMash [197]
3 years ago
13

a 1 kg emery stone measuring 20 cm redium, is rotating with an angular speed of 39 revolutions per minute, when the motor is tur

ned off. What tangent force is applied to the wheel so that it stops at 10 revolutions. a. Answer: 12,24 Rand/s b. Answer:13,24 Rand/s c. Answer: 10,4 Rand/s d. Answer: 124 Rand/s
Physics
1 answer:
musickatia [10]3 years ago
3 0

Answer: 13,24

Explanation:

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a car travels West 50km for 2 hours before heading south at a rate of 30 km per hour for 1.5 hours. What is the car's average sp
inn [45]

Answer:

Explanation:

average speed is distance traveled over time

v = (50 + 30(1.5)) / (2 + 1.5) = 27.1428571...

v = 27 km/hr

6 0
3 years ago
What is hooke's law? Also what does it say about how elastic materials respond to force? Explain.
gogolik [260]
It <span>states that the force F needed to extend or compress a spring by some distance X is proportional to that distance.

For elastic materials, they extend more in same amount of force, (as they are directly proportional), due to it's elastic nature (presence of large deforming force)

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3 0
3 years ago
A 70- kg bicycle rides his 9.8- kg bicycle with a speed of 16 m/ s. What is the magnitude of the braking force of the bicycle co
Rus_ich [418]

Answer:

F = -319.2 N

Explanation:

Given that,

The mass of a bicyclist, m = 70 kg

Mass of the bicycle = 9.8 kg

The speed of a bicycle, v = 16 m/s

We need to find the magnitude of the braking force of the bicycle come to rest in 4.0 m.

The braking force is given by :

F=ma\\\\=\dfrac{m(v-u)}{t}\\\\=\dfrac{(70+9.8)(0-16)}{4}\\\\=-319.2\ N

So, the required force is 319.2 N.

3 0
3 years ago
A crowbar 2727 in. long is pivoted 66 in. from the end. What force must be applied at the long end in order to lift a 600600 lb
NikAS [45]

To solve this problem we will apply the concepts related to equilibrium, for this specific case, through the sum of torques.

\sum \tau = F*d

If the distance in which the 600lb are applied is 6in, we will have to add the unknown Force sum, at a distance of 27in - 6in will be equivalent to that required to move the object. So,

F*(27-6)= 6*600

F = \frac{6*600}{21}

F= 171.42 lb

So, Force that must be applied at the long end in order to lift a 600lb object to the short end is 171.42lb

4 0
3 years ago
Isaac Newton published his work on gravity in the Philosophiæ Naturalis Principia Mathematica (Latin for Mathematical Principles
Igoryamba
Today we can make observations that would lead us to the same conclusion as newton. If you throw a baseball in the air, it always comes back down. This is because of gravity. duh.
6 0
3 years ago
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