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Usimov [2.4K]
3 years ago
8

Which major regions had the Romans controlled?

Physics
1 answer:
alexandr402 [8]3 years ago
5 0
From 200 BC to around 14 AD, Rome had conquered most of Western Europe, Greece and the Balkans. Also the Middle East, and North Africa.
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What is the logical oreder for these words : verse, interlude,verse,refrain, introduction,refrain,coda,refrain,verse
Nikolay [14]

Sorry to say but I know that t(e introduction is first and the coda is last


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4 years ago
Help!!!<br>middle school physics ​also please explain :)
Dmitriy789 [7]

Answer:

hope its helps

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8 0
3 years ago
When a low-pressure gas of hydrogen atoms is placed in a tube and a large voltage is applied to the end of the tube, the atoms w
FromTheMoon [43]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The value of n is n =7

Explanation:

    From the question we are told that

          The value of m = 2

            For every value of m, n = m+ 1, m+2,m+3,....

           The modified version of  Balmer's formula is \frac{1}{\lambda}  = R [\frac{1}{m^2} - \frac{1}{n^2}  ]

             The Rydberg constant has a value of R = 1.097 *10^{7} m^{-1}

The objective of this solution is to obtain the value of n for which the wavelength of the Balmer series line is smaller than 400nm

   

For m = 2 and n =3

    The wavelength is

                          \frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{3^2}  ]

                          \lambda = \frac{1}{1523611.1112}

                             \lambda = 656nm

For m = 2 and n = 4

    The wavelength is

                          \frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{4^2}  ]

                          \lambda = \frac{1}{2056875}

                             \lambda = 486nm

For m = 2 and n = 5

    The wavelength is

                          \frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{5^2}  ]

                          \lambda = \frac{1}{2303700}

                             \lambda = 434nm

For m = 2 and n = 6

    The wavelength is

                          \frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{6^2}  ]

                          \lambda = \frac{1}{2422222}

                             \lambda = 410nm

For m = 2 and n = 7

    The wavelength is

                          \frac{1}{\lambda } = (1.097 * 10^7)[\frac{1}{2^2} - \frac{1}{7^2}  ]

                          \lambda = \frac{1}{2518622}

                             \lambda = 397nm

So the value of n is  7

7 0
3 years ago
Please solve this problem!​
siniylev [52]

Answer:

Send a clear photo again

Explanation:

And tag me

6 0
3 years ago
A runner is training for an upcoming marathon by running around a 80-m-diameter circular track at constant speed. Let a coordina
Umnica [9.8K]

Answer:

Explanation:

Given

diameter d=80\ m

runner start at (x,y)=(48 m,0 m)

Runner runs around the circle 2.5 times

i.e. he runs two and half rounds

displacement of two rounds is zero so net displacement is of half round

displacement =\pi \cdot 48=150.816\ m

After 2.5 round he will be towards west direction with respect to origin

so direction of displacement vector is west

7 0
4 years ago
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