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bekas [8.4K]
4 years ago
5

In a double-slit interference experiment, interference fringes are observed on a distant screen. The width of both slits is then

doubled without changing the distance between their centers.
a. What happens to the spacing of the fringes?
b. What happens to the intensity of the bright fringes?
Physics
1 answer:
Lubov Fominskaja [6]4 years ago
7 0

Answer:a)It remains the same.

b)It decreases

Explanation:◇y = (wavelength×Length)/ distance

The wavelength of light is constant.

d = distance between the two slit. The value of d does not change so the fringes as well will not change.

b) As the space between the two slit becomes wider,the diffraction of light waves will become wider too.

When the width of the two slits are doubled,the diffraction of light forms larger angles and the intensive of the bright fringes decreases.

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Three joggers are running along straight lines as follows: Jogger A, with a mass of 55.2kg, is traveling along the line y=6.00m
frutty [35]

Answer:

L = - 1361.591 k Kgm/s

Explanation:

Given

mA = 55.2 Kg

vA = 3.45 m/s

rA = 6.00 m

mB = 62.4 Kg

vB = 4.23 m/s

rB = 3.00 m

mC = 72.1 Kg

vC = 4.75 m/s

rC = - 5.00 m

then we apply the equation

L =  (mv x r)

⇒  LA = mA*vA x rA = 55.2 *(3.45 i)x(6 j) = (1142.64 k) Kgm/s

⇒  LB = mB*vB x rB = 62.4 *(4.23 j)x(3 i) = (- 791.856 k) Kgm/s

⇒  LC = mC*vC x rC = 72.1 *(- 4.75 j)x(- 5 i) = (- 1712.375 k) Kgm/s

Finally, the total counterclockwise angular momentum of the three joggers about the origin is

L = LA + LB + LC = (1142.64 - 791.856 -1712.375) k  Kgm/s

L = - 1361.591 k Kgm/s

7 0
3 years ago
A racing car travels on a circular track of radius 158 m, moving with a constant linear speed of 19.1 m/s. Find its angular spee
SOVA2 [1]

Answer:

\omega=0.12\frac{rad}{s}

Explanation:

In a uniform circular motion, since a complete revolution represents 2π radians, the angular velocity, which is defined as the angle rotated by a unit of time, is given by:

\omega=\frac{2\pi}{T}(1)

Here T is the period, that is, the time taken to complete onee revolution:

T=\frac{2\pi r}{v}(2)

Replacing (2) in (1):

\omega=\frac{2\pi}{\frac{2\pi r}{v}}=\frac{v}{r}\\\omega=\frac{19.1\frac{m}{s}}{158m}\\\omega=0.12\frac{rad}{s}

3 0
4 years ago
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d1i1m1o1n [39]

Answer:

Answer for the question is given in the attachment.

Explanation:

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3 years ago
What does training for hypertrophy do to your body
VikaD [51]

Answer:

The answer is A.

Explanation:

Hypertrophy is an increase and growth of muscle cells. Hypertrophy refers to an increase in muscular size achieved through exercise. When you work out, if you want to tone or improve muscle definition, lifting weights is the most common way to increase hypertrophy.

Hope that helped.

5 0
3 years ago
Read 2 more answers
A young girl slides down a rope. As she slides
hodyreva [135]

Answer:

The girl will move with constant velocity

Explanation:

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The girl will move with constant velocity,as explained above.

6 0
3 years ago
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