Answer:
5 m
Explanation:
Speed of waves is as the product of frequency and wavelength hence expressed as s=fw where f is the frequency of waves in Hz, s is the speed in m/s and w is wavelength in meters.
Making w the subject of the formula then
Substituting 335 m/s for s and 67 Hz for f then the wavelength is
Wavelength is the distance between successive crests. Since the string is 10m, wavelengths of 5m each will be 2 and the crests will be 3.
Wavelenth=5 m
Answer: 20.73m/s
Explanation:
The question simply wants us to calculate the speed of the pitch. The speed will be calculated as:
= Distance/Time
where,
Distance = 85 meters
Time = 4.1 seconds
Speed = Distance/Time
Speed = 85/4.1
Speed = 20.73m/s
Therefore, the speed of the pitch is 20.73m/s.
The correct answer to the question is : D) 352.6 m/s.
CALCULATION :
As per the question, the temperature is increased from 30 degree celsius to 36 degree celsius.
We are asked to calculate the velocity of sound at 36 degree celsius.
Velocity of sound is dependent on temperature. More is the temperature, more is velocity of sound.
The velocity at this temperature is calculated as -
V = 331 + 0.6T m/s
= 331 + 0.6 × 36 m/s
= 331 + 21.6 m/s
= 352.6 m/s.
Here, T denotes the temperature of the surrounding.
Hence, velocity of the sound will be 352.6 m/s.
Answer: 0.313 rad/s
Explanation:
The equation that relates the velocity 
and the angular velocity 
in the uniform circular motion is:
(1)
Where 
is the radius of the space station (with a diaeter of 200m) that describes the uniform circular motion.
Isolating from (1):
(2)
On the other hand, we are told the “artificial gravity” produced by the cetripetal acceleration 
is 
, and is given by the following equation:
(3)
Isolating :
(4)
(5)
Substitutinng (5) in (2):
(6)
This is the angular velocity that would produce an “artificial gravity” of 9 .
