I really need help please

A sample of a substance that has a density of 0.824 g/mL has a mass of 0.451g. Calculate the volume of the sample.

Allushta [10]

Density can be calculated using the following rule:
density=mass/volume
therefore,
volume=mass/density

we have mass=0.451g and density=0.824g/ml
substituting in the above equation, we can calculate the volume as follows:
volume = 0.451/0.824 = 0.547 ml

8 0

3 years ago

PLZ HELP Which factors play a role in creating ocean waves?

Yuki888 [10]

Answer:

all of these

Explanation:

4 0

3 years ago

Read 2 more answers

can you tell what the genotype of the purple flowered parent is from the information in the punnets square? explain why or why n

Nina [5.8K]

We will not be able to tell the genotype of the purple parent as it can either be a homo_zygous dominant or hetero_zygous. Without the complete genotype of the offspring, we would not be able to tell.

6 0

2 years ago

Garfield (weighing 24 lbs) took a flight from the earth to the moon (where the gravity is 1/6 the gravity here on earth) on the

Nana76 [90]

Answer:

Reason: Gravitational pull of the Moon

Explanation:

Weight of Garfield is 24 lbs on the Earth. He took a flight from the Earth to the Moon where the gravity is 1/6 of the gravity on the Earth.

But when reaches the Moon he found he weighed only 6 lbs. It is due to the gravitational pull of the Moon.

Mass of an object reamins the same at every location while its weight changes due to the change in acceleration due to gravity. It is equal (on Moon) to 1/6 the of acceleration due to gravity on the earth.

3 0

3 years ago

Pls tell me how to solve this!

Anna35 [415]

Answer:

12 seconds

Explanation:

Time taken by 50cm³ of oxygen to diffuse from pinhole

= 1 minute = 60 seconds

⠀

$\textsf{ Rate of oxygen} \sf (O_2) = \frac{50}{60}$

⠀

Let time taken by 50cm³ of hydrogen to diffuse from pinhole = t seconds

⠀

$\textsf {Rate of hydrogen } \sf(H_2) = \frac{50}{t}$

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According to the formula

$\sf \frac{Rate \: of \: hydrogen(H_2)}{Rate \: of \: oxygen(O_2) } = \sqrt{ \frac{Molar \: mass \: of \: O_2}{Molar \: mass \: of \: H_2} }$

⠀

$\large \sf \frac{50}{t} \div \frac{50}{60} = \sqrt{ \frac{\cancel{32}\small 16}{\cancel2} } \\ \\ \sf \large \frac{ \cancel{50}}{t} \times \frac{60}{ \cancel{50}} = \sqrt{16} \\ \\ \sf \large \frac{60}{t} = 4 \\ \\ \sf \large \frac{ \cancel{60} \: \small12}{ \cancel4} = t \\ \\ \large \underline{ \boxed{ \tt t = 12 \: seconds}}$

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<h3>Henceforth, the time taken by 50cm³ of hydrogen to diffuse is 12 seconds. </h3>

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<h2>Thank you!</h2>

8 0

1 year ago