Answer:
Option A: F/4
Explanation:
Centripetal force,
Where v = speed
r = radius
Since Kinetic Energy,
Writing centripetal force in terms of kinetic energy,
If the initial radius of the circle, r₁ =r
The doubled radius, r₂ = 2r
If the initial kinetic energy,
The halved kinetic energy,
Therefore, the new Centripetal force becomes:
Answer:
Explanation:
Total frictional force on boxes
= total weight x coefficient of friction
= ( 11 + 7 ) x 9.8 x .02 = 3.53 N
Net force on boxes
= 8.9 - 3.53
= 5.37 N
acceleration = 5.37 /( 11 + 7 )
= 0.3 m / s ²
b ) Let us consider movement of block A ( 11 kg )
acceleration a = .3 m/s²
friction force on block A
11 X 9.8 X .02
= 2.156 N
Net force on block A
8.9 - friction force - reaction force by block B
= 8.9 - 2.156 - F_ c
force = mass x acceleration
8.9 - 2.156 - F_ c = 11 x .3
F_ c = 3.444 N
c )
If force is applied from the side of box B
We consider all forces on box B
frictional force on it
= 7 x 9.8 x .02
= 1.372 N
Net force on it
8.9 - 1.372 - F_c
force = mass x acceleration
= 8.9 - 1.372 - F_c = 7 x .3 ( Acceleration of box B will be the same that is 0.3 m/s² )
F_c = 5.428 N
Answer:
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Answer:
190v I believe
hope this helped a little and if it did pls mark brainiest :)