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lions [1.4K]
2 years ago
9

What happens to the gravitational force between two objects if:

Physics
1 answer:
tiny-mole [99]2 years ago
5 0

Answer:

See the answers below

Explanation:

This problem and its respective questions can be easily solved using Newton's law of universal gravitation. Which can be calculated by means of the following expression.

F =G*\frac{m_{1}*m_{2}}{r^{2} }

where:

G = it is the universal gravitation constant. = 6.673 x 10⁻¹¹ [N*m²/kg²]

m1 = mass of the first body [kg]

m2 = mass of the second body [kg]

r = distance among the bodies [m]

a. the mass of one is doubled?

When this happens we see that the force is increased twice as well, since the mass is in the numerator of the expression.

b. The masses of both are doubled?

If both masses are doubled the force is increased to four times its original value since the terms of the masses are in the numerator of the expression.

c. The distance between them is doubled?

In this case the force is decreased to half of its original value, since the distance is in the denominator of the expression of universal gravitation.

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In a science fiction novel two enemies, Bonzo and Ender, are fighting in outer spce. From stationary positions, they push agains
Hoochie [10]

Answer:

\frac{m_B}{m_E}=1.18

Explanation:

m_B = Mass of Bonzo

m_E = Mass of Ender

u_B = Initial Velocity of Bonzo = 2.2 m/s

u_E = Initial Velocity of Ender = -2.6 m/s

From conservation of linear momentum

m_Bu_B=m_Eu_E\\\Rightarrow \frac{m_B}{m_E}=\frac{u_E}{u_B}\\\Rightarrow \frac{m_B}{m_E}=\frac{2.6}{2.2}\\\Rightarrow \frac{m_B}{m_E}=1.18

\therefore \frac{m_B}{m_E}=1.18

8 0
3 years ago
What is the weight of an object when the object has a mass of 22kg
Savatey [412]
Assuming the object is on earth the objects weight would be equal to its mass multiplied by the gravitational field constant

mass=22kg
g=9.80665N/kg

weight=(22 kg) (9.80665 N/kg)=215.7463N

generally g is rounded to be 10 N/kg so for any question where it asks the weight given the mass just multiply by 10 and that should suffice. In this case the answer would be 220 N
5 0
2 years ago
Hey can someone please help answer this question?
yan [13]

Answer:

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Explanation: is good

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2 years ago
A musical tone sounded on a pi has frequency of 410 Hz and a wavelength of 0.80 m.
spayn [35]
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4 0
3 years ago
A motorcycle has a mass of 2.50×10^2. A constant force is exerted on it for 60.0s. The motorcycles initial velocity is 6.00 m/s
Margarita [4]

The change in momentum is 5500 kg m/s

Explanation:

The change in momentum of an object is given by

\Delta p = m(v-u)

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have:

m=2.50\cdot 10^2 kg (mass of the motorcycle)

v=28.0 m/s (final velocity)

u=6.0 m/s (initial velocity)

Therefore, the change in momentum is

\Delta p=(2.50\cdot 10^2)(28.0-6.0)=5500 kg m/s

Learn more about change in momentum:

brainly.com/question/9484203

#LearnwithBrainly

8 0
3 years ago
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