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gavmur [86]
3 years ago
9

How many moles are there in 1.68 * 10 ^ 24 molecules of nitrogen dioxide?

Chemistry
1 answer:
padilas [110]3 years ago
3 0

Answer:

<h2>2.79 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{1.68 \times  {10}^{24} }{6.02 \times  {10}^{23} } \\  = 2.790697 ...

We have the final answer as

<h3>2.79 moles</h3>

Hope this helps you

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B. It is important that people are not harmed for the sake of science.

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What would be the volume in liters of 640g of oil if the density of the oil is 0.8g/mL
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Hey there!

Mass = 640 g

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Therefore:

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Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow
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Explanation:

(a)  The given data is as follows.

              Pressure on top (P_{o}) = 140 bar = 1.4 \times 10^{7} Pa       (as 1 bar = 10^{5})

              Temperature = 15^{o}C = (15 + 273) K = 288 K

         Density of gas = \frac{PM}{ZRT}

                \frac{dP}{dZ} = \rho \times g

               \frac{dP}{dZ} = \int \frac{PM}{ZRT}

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           ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}

                              = 0.4548

                     P_{1} = P_{o} \times e^{0.4548}

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(b)   At the bottom of the tank,

                 P_{2} = P_{1}  + \rho \times g \times h

                             = 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

                             = 309.8 \times 10^{5} Pa

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