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anygoal [31]
3 years ago
11

Hello, I have three questions to ask! It's very important, and it would be amazing if you could help me answer it :)!

Physics
2 answers:
geniusboy [140]3 years ago
8 0

Answer:

Explanation:

true

liq [111]3 years ago
8 0
1.) The bat exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat. This is the reaction force.

2.) True! The force of the bug on the windshield is equal to the force of the windshield on the bug, only in the opposite direction.

3.) This is Newton’s third law and the total momentum of the two objects before the collision is the same as the total momentum of the two objects after the collision. (Reaction) The momentum of each object may change, but the total momentum must remain the same.
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a toy dart gun generates a dart with .140kg.m/s momentum and a velocity of 4m/s. what is the mass of the dart in grams?
sleet_krkn [62]

Answer: m = 0.035kg = 35g

Explanation: Momentum p=0.140kgm/s

Velocity v=4m/s

Mass m=?

Formula-

Momentum depends on the mass of the object in motion and its velocity.

The equation for momentum is

p = mv

m = p/v

m = 0.140/4

m = 0.035kg

m = 35g

Hence, in the toy dart gun mass of the dart is 0.035kg.

4 0
2 years ago
Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta
Colt1911 [192]
<span>B: adds aesthetic value to the landscape. Think about it, out of all your options, that's the one that doesn't really help anything.

And I took the test, so take my word for it.</span>
6 0
3 years ago
A 0.500-kg block, starting at rest, slides down a 30.0° incline with static and kinetic friction coefficients of 0.350 and 0.250
Leviafan [203]

Answer:x=23.4 cm

Explanation:

Given

mass of block m=0.5 kg

inclination \theta =30

coefficient of static friction \mu =0.35

coefficient of kinetic friction \mu _k=0.25

distance traveled d=77.3 cm

spring constant k=35 N/m

work done by gravity+work done by friction=Energy stored in Spring

mg\sin \theta d-\mu _kmg\cos \theta d=\frac{kx^2}{2}

mgd\left ( \sin \theta -\mu _k\cos \theta \right )=\frac{kx^2}{2}

0.5\times 9.8\times 0.773\left ( \sin 30-0.25\cos 30\right )=\frac{35\times x^2}{2}

x=\sqrt{\frac{2\times 0.5\times 9.8\times 0.773(\sin 30-0.25\times \cos 30)}{35}}

x=0.234 m

x=23.4 cm

6 0
3 years ago
True or False. Centripetal force holds an object towards the center of a circle.
Flura [38]
False’ because it is a force that makes a body follow a curved path
7 0
3 years ago
How much power does it take to lift 30.0 N 10.0 m high in 5.00 s?
Rudik [331]

Power = work/time = (Force times distance)/time

= (30N *10.0m)/5.00s = 300/5 = 60 Watts

7 0
3 years ago
Read 2 more answers
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