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fgiga [73]
3 years ago
11

Find V V=25m. _____=?? 3.5s.

Physics
1 answer:
matrenka [14]3 years ago
4 0

Answer:

?

Explanation:

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Two blocks are connected by a massless rope. The rope passes over an ideal (frictionless and massless) pulley such that one bloc
Rainbow [258]

Answer:

Explanation:

asd

4 0
3 years ago
Energy of fossil fuels is also derieved from solar energy​
Marat540 [252]

Answer:

Explanation:

All the energy in oil, gas, and coal originally came from the sun, captured through photosynthesis.for example when  we burn wood to release energy that trees capture from the sun, we burn fossil fuels to release the energy that ancient plants captured from the sun. We can think of this energy as having been deposited in a natural solar power bank over millions of years.

So, in one sense, gasoline-burning cars, coal-burning power plants, and homes heated by natural gas are all solar powered!

6 0
3 years ago
A mass weighing 11 lb stretches a spring 4in. The mass is pulled down an additional 3 in and is then set in motion with an initi
Shtirlitz [24]

Answer:

a) x(t) = 2.845\cdot \cos \left(1.732\cdot t -0.473\pi \right), b) T = 3.628\,s, A = 2.845\,ft, \phi = -0.473\pi

Explanation:

a) The system mass-spring is well described by the following equation of equilibrium:

\Sigma F = k\cdot x - m\cdot g = m\cdot a

After some handling in physical and mathematical definition, the following non-homogeneous second-order linear differential equation:

\frac{d^{2}x}{dt^{2}}+\frac{k}{m}\cdot x = g

The solution of this equation is:

x (t) = A\cdot \cos \left(\sqrt{\frac{k}{m} } \cdot t + \phi\right)

The velocity function is:

v(t) = \sqrt{\frac{k}{m} }\cdot A\cdot \sin \left(\sqrt{\frac{k}{m} }\cdot t +\phi  \right)

Initial conditions are:

x(0\,s) = 0.25\,ft, v(0\,s) = -5\,\frac{ft}{s}

Equations at t = 0\,s are:

0.25\,ft =  A\cdot \cos \phi\\-5\,\frac{ft}{s} =\sqrt{\frac{k}{m} }\cdot A\cdot \sin \phi

The spring constant is:

k = \frac{11\,lbf}{0.333\,ft}

k = 33\,\frac{lbf}{ft}

After some algebraic handling, amplitude and phase angle are found:

\phi = -0.473\pi

A = 2.845\,ft

The position can be described by this function:

x(t) = 2.845\cdot \cos \left(1.732\cdot t -0.473\pi \right)

b) The period of the motion is:

T = \frac{2\pi}{\sqrt{\frac{k}{m} } }

T = 3.628\,s

The amplitude is:

A = 2.845\,ft

The phase of the motion is:

\phi = -0.473\pi

8 0
4 years ago
A long pipe of outer radius R 1 = 3.70 cm and inner radius R 2 = 3.15 cm carries a uniform charge density of 1.22 mC/m 3 . Assum
7nadin3 [17]

Answer:

E = 4.72 * 10⁻⁶ Nm²

Explanation:

Parameters given:

Outer radius, R = 3.70cm = 0.037m

Inner radius, r = 3.15cm = 0.0315m

Permittivity of free space, ε₀ = 8.85 * 10⁻¹² C/Nm²

Charge density: 1.22 * 10⁻³ C/m³

The question requires that we solve using Gauss law which states that the net electric field through a closed surface is proportional to the enclosed electric charge.

Hence,

E = Q/Aε₀

Charge Q is given as

Q = ρπ(R² ⁻ r²)L

A = 2π(R - r)L

E = [ρπ(R² ⁻ r²)L]/[2π(R - r)ε₀L]

Using difference of two squares,

(R² ⁻ r²) = (R + r)(R - r)

E =[ρ(R + r)]/(2ε₀)

E = [1.22 * 10⁻³ *(0.0370 + 0.0315)]/(2 * 8.85 * 10⁻¹²)

E = 4.72 * 10⁻⁶ Nm²

6 0
4 years ago
I WILL MARK YOU AS BRAINLIEST IF RIGHT
butalik [34]

Answer:

25.4 miles per hour

Explanation:

speed=distance/time

speen=524/20.6 hours

=25.4 miles per hour

6 0
4 years ago
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