A (4,8) and b (7,2) and let c (x,y)
A , B and C are col-linear ⇒⇒⇒ ∴ slope of AB = slope of BC
slope of AB = (2-8)/(7-4) = -2
slope of BC = (y-2)/(x-7)
∴ (y-2)/(x-7) = -2
∴ (y-2) = -2 (x-7) ⇒⇒⇒ equation (1)
<span>The distance
between two points (x₁,y₁),(x₂,y₂) = d
</span>
The ratio of AB : BC = 3:2
AB/BC = 3/2
∴ 2 AB = 3 BC

= <span>

eliminating the roots by squaring the two side and simplifying the equation
∴ 4 * 45 = (x-7)² + (y-2)² ⇒⇒⇒ equation (2)
substitute by (y-2) from equation (1) at </span><span>equation (2)
4 * 45 = 5 (x-7)²
solve for x
∴ x = 9 or x = 5
∴ y = -2 or y = 6
The point will be (9,-2) or (5,6)
the point (5,6) will be rejected because it is between A and B
So, the point C = (9,-2)
See the attached figure for more explanations
</span>
The answer:
according to the image, the main theorem concerning right triangle similarity is as follow:
the altitude to the hypotenuse of a right triangle divides the triangle into two triangles that are similar to the original triangle and each other,
in our case, KL is the altitude, and by applying theorem, we get three triangles that are similar:
therefore:
<span>△JKL ~ △JKM
</span><span>△JKM ~ △JKM
</span><span>△JMK ~ △KML</span>
Answer:
Step-by-step explanation:
1. Angle 4 is congruent to angle 6
2. Angle 3 is congruent to angle 5
Let U={1,2,3,4,5,6,7,8}A={2,3,6}B={2,4,5,7}C={1,7,8}Find the following use the roster method to write method to write the set. E
Ipatiy [6.2K]
A U B = set of all elements that are in both A or B:
A U B = {2, 3, 4, 5, 6, 7}
Here is a picture to see our answer.
fndadhfuhadifhaStep-by-step explanation: