<h3>
Answer:</h3>
1.93 g
<h3>
Explanation:</h3>
<u>We are given;</u>
The chemical equation;
2C₂H₆(g) + 7O₂(g) → 4CO₂(g) + 6H₂O(l) ΔH = -3120 kJ
We are required to calculate the mass of ethane that would produce 100 kJ of heat.
- 2 moles of ethane burns to produce 3120 Kilo joules of heat
Number of moles that will produce 100 kJ will be;
= (2 × 100 kJ) ÷ 3120 kJ)
= 0.0641 moles
- But, molar mass of ethane is 30.07 g/mol
Therefore;
Mass of ethane = 0.0641 moles × 30.07 g/mol
= 1.927 g
= 1.93 g
Thus, the mass of ethane that would produce 100 kJ of heat is 1.93 g
Answer:
jjiooyfffffffffffcvģg5fffvgvvvhh
Explanation:
jhhhhuxjcififigigivigviigiggivi
We’re going to use the mass percent formula shown below:
For the percent by mass N, we’re going to rewrite the equation as:
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Problem Details
Calculate the mass percent composition of nitrogen in each nitrogen-containing compound:
c. NO2
Answer:
VC = 18
Explanation:
Since L is the midpoint and you have LV, you know that LC is also 9.
