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MrRa [10]
3 years ago
6

A 625 kg elevator is pulled upward by a cable that exerts a 7250 N force. What is the acceleration of the elevator?(Don't forget

its weight)
Physics
2 answers:
Olegator [25]3 years ago
8 0

Answer:

The acceleration of the elevator is 1.8 m/s².

Explanation:

Given that,

Mass of elevator = 625 kg

Tension = 7250 N

We need to calculate the acceleration

Using equation of balance

T-mg=ma

Where, T = tension

m = mass

a = acceleration

Put the value into the formula

7250-625\times9.8=625\times a

a=\dfrac{7250-625\times9.8}{625}

a=1.8\ m/s^2

Hence, The acceleration of the elevator is 1.8 m/s².

Kitty [74]3 years ago
6 0

Answer:

1.6ms^2

Explanation:

7250=625(g+a)

11.6=10+a

1.6=a

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If a 990 kg car is on the road and the Ff is 360 n what is the normal force
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Read 2 more answers
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