Answer:
nail will stop after traveling 1000 m
Explanation:
We have given mass m = 50 gram = 0.05 kg
Frictional force which is used to stop the mass F = 62.5 kN
Initial velocity is given u = 50 m/sec
From newton's law force is equal to F = ma, here m is mass and a is acceleration
So 
As finally nail stops so final velocity v = 0 m/sec
From third equation of motion 
So 
s = 1000 m
So nail will stop after traveling 1000 m
Answer:
The work done to lift the counterweight equals the potential energy acquired
Explanation:
since this is vertically applied force on the counterweight, and the distance the force is displacing the counterweight is in the same direction as the applied force, it equals the gained potential energy
Answer:
c. 65
Explanation:
The output is 65.
An array of length 10 is created first. Then, the first for-loop fill the array with different values; The array element now become: 2, 3, 4, 5, 6, 7, 8, 9, 10, 11. The array element are generated using the equation a[i] = i + 2; so when i is 0, 1, 2, 3, 4, 5, 6, 7, 8, 9. i must be less than the array length (10).
a[0] = 0 + 2 = 2
a[1] = 1 + 2 = 3
a[2] = 2 + 2 = 4
a[3] = 3 + 2 = 5
a[4] = 4 + 2 = 6
a[5] = 5 + 2 = 7
a[6] = 6 + 2 = 8
a[7] = 7 + 2 = 9
a[8] = 8 + 2 = 10
a[9] = 9 + 2 = 11
result variable is declared and initialized to 0.
The second for-loop goes through the array and add individual element to result.
Answer:
a= 2.7 m/s^2
Explanation:
acceleration: a
speed: V
Vf = final speed
Vi= initial speed (initial = beginning)
100 km/hour --> m/s
divide the speed value by 3.6
100/3.6= 27.8 m/s
a= 2.7 m/s^2
