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Kisachek [45]
3 years ago
6

The combustion of propane C,H, produces carbon dioxide and steam.

Chemistry
1 answer:
Julli [10]3 years ago
7 0

Answer:

23 moles

Explanation:

Given data:

number of moles of propane = 7.5 mol

Number of moles of carbon dioxide produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂     →      3CO₂ + 4H₂O

Now we will compare the moles of propane and carbon dioxide.

                        C₃H₈             :             CO₂

                             1                :               3

                           7.5              :           3/1×7.5 = 22.5

22.5≅ 23 moles

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How many atoms are in lead ii bicarbonate​
sertanlavr [38]

Answer:

11 atoms

Explanation:

The formula for lead(II) bicarbonate is: Pb(HCO3)2.

Atoms in Pb(HCO3)2:

Pb=1, H=1×2, C=1×2, O=3×2

1+1×2+1×2+3×2

=1+2+2+6

=11 atoms

4 0
4 years ago
Express your answer to three significant figures and include appropriate units
nata0808 [166]

Answer:

58.702

Explanation:

Data obtained from the question include:

Mass number of isotope 1 (M1) = 57.93

Abundance of isotope 1 (M1%) = 67.76%

Mass number of isotope 2 (M2) = 59.93

Abundance of isotope 2 (M2%) = 26.16%

Mass number of isotope 3 (M3) = 60.93

Abundance of isotope 3 (M3%) = 1.25%

Mass number of isotope 4 (M4) = 61.93

Abundance of isotope 4 (M4%) = 3.66%

Mass number of isotope 5 (M5) = 63.93

Abundance of isotope 5 (M5%) = 1.16%

Relative atomic mass =...?

The relative atomic mass(RAM) of the element can be obtained by doing the following:

RAM = [(M1×M1%) /100] +[(M2×M2%) /100] + [(M3×M3%) /100] + [(M4×M4%) /100] + [(M5×M5%) /100]

RAM = [(57.93×67.76)/100] + [(59.93×26.16)/100] + [(60.93×1.25) /100] + [(61.93×3.66)/100] + [(63.93×1.16)/100]

RAM = 39.253 + 15.678 + 0.762 + 2.267 + 0.742

RAM = 58.702

Therefore, the relative atomic mass (RAM) of the element is 58.702

7 0
3 years ago
Using the information in the table to the right, calculate the enthalpy of combustion of 1 mole of acetylene for the reaction
barxatty [35]

The enthalpy of combustion of 1 mole of acetylene for the reaction using the information in the table (attached as figure) is - 1,256 kJ/mol

<h3>What is Enthalpy of combustion ?</h3>

The enthalpy of combustion of a substance is defined as the heat energy given out when one mole of a substance burns completely in oxygen.

Hence, The enthalpy of combustion of 1 mole of acetylene for the reaction using the information in the table is - 1,256 kJ/mol

Learn more about Enthalpy here ;

brainly.com/question/16720480

#SPJ1

8 0
3 years ago
The molar mass of KCl is 74. 55 g/mol. If 8. 45 g KCl are dissolved in 0. 750 L of solution, what is the molarity of the solutio
rosijanka [135]

Molarity is the strength of the solution or the ratio of the moles and the volume of the solution. The molarity of the solution is 0.1516 mol per Liter.

<h3>What is molarity?</h3>

Molarity is the molar concentration of the solution that tells about the amount of the solute or the substance dissolved in the given amount of the solution.

Given,

  • Mass of potassium chloride = 8.45 g
  • Molar mass of potassium chloride = 74. 55 g/mol
  • Volume of the solution = 0.750 L

Moles can be calculated by:

\begin{aligned}\rm Moles &= \rm \dfrac{Mass }{\rm Molar \;mass}\\\\&= \dfrac{8.45}{74.55}\\\\&= 0.1133\;\rm  mol\end{aligned}

Calculate molarity by:

\rm Molarity = \dfrac{moles}{\text{Volume in L}}

Substituting values in the equation:

\begin{aligned}\rm  Molarity &= \dfrac{0.1133}{0.750}\\\\&= 0.1516 \;\rm mol\;L^{-1}\end{aligned}

Therefore, the molarity of the solution is 0.1516 mol per Liter.

Learn more about molarity here:

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4 0
2 years ago
Describe two ways you could demonstrate an acceleration of 2 meters per second squared?
BaLLatris [955]

Answer:

You could do 88 metars  

Explanation:

7 0
3 years ago
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