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likoan [24]
1 year ago
5

How many grams of carbon are contained in 2.25 g of potassium carbonate, K2CO3

Chemistry
1 answer:
romanna [79]1 year ago
5 0

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

<h3>Molecular mass of potassium carbonate</h3>

The molecular mass of potassium carbonate, K₂CO₃ is calculated as follows;

M = K₂CO₃

M = (39 x 2) + (12) + (16 x 3)

M = 138 g

mass of carbon in potassium carbonate, K₂CO₃ is = 12 g

The mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is calculated as follows;

138 g ------------ 12 g of carbon

2.25 g ------------ ?

= (2.25 x 12) / 138

= 0.196 g

Thus, the mass of carbon contained in 2.25 g of potassium carbonate, K₂CO₃ is 0.196 g.

Learn more about potassium carbonate here: brainly.com/question/27514966

#SPJ1

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Answer:

159 mg caffeine is being extracted in 60 mL dichloromethane

Explanation:

Given that:

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The portion of the DCM = 60 mL

Partial co-efficient (K) = \frac{C_1}{C_2}

where; C_1= solubility of compound in the organic solvent and C_2 = solubility in aqueous water.

So; we can represent our data as:

K=(\frac{A_{(g)}}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL} )

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4.6=(\frac{0.6-B(mg)}{60mL} ) ÷ (\frac{B_{(mg)}}{100mL})

4.6 = \frac{(\frac{0.6-B(mg)}{60mL} )}{(\frac{B_{(mg)}}{100mL})}

4.6 × (\frac{B_{(mg)}}{100mL}) = (\frac{0.6-B(mg)}{60mL} )

4.6 B *\frac{60}{100} = 0.6 - B

2.76 B = 0.6 - B

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∴ 159 mg caffeine is being extracted from the 100 mL of water containing 600 mg of caffeine with one portion of in 60 mL dichloromethane.

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