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Harrizon [31]
2 years ago
6

How does the chemistry of life relate to cellular respiration

Chemistry
1 answer:
storchak [24]2 years ago
3 0

Answer:

¿Cuál es la reaccion quimica de la respiracion celular?

La respiración celular es una reacción exergónica, donde parte de la energía contenida en las moléculas de alimento es utilizada por la célula para sintetizar ATP. ... Aproximadamente el 40% de la energía libre emitida por la oxidación de la glucosa se conserva en forma de ATP.

Explanation:

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Hi can someone please help me find the average for these temperatures? I need them asap
goblinko [34]

Answer:

55 degrees F - cold water

120 degrees F

the last on I don't know

5 0
2 years ago
Two amino acids frequently found in reverse turns are a. glycine and proline b. tyrosine and tryptophan c. leucine and isoleucin
Crank

Answer:

A

Explanation:

Polypeptides such as proline and glycine are capable of making a sharp turn called a reverse turn due to the suitability and flexibility of their cyclic structure

8 0
2 years ago
Read 2 more answers
Which is and element <br> A) Salad<br> B) Sugar<br> C) Water <br> D) Potassium
Semenov [28]

Answer:

the only element above is potassium

3 0
3 years ago
Current passes through a solution of sodium chloride. In 1.00 second, 2.68×1016Na+ ions arrive at the negative electrode and 3.9
EleoNora [17]

Answer : The current passing between the electrodes is, 1.056\times 10^{-2}A

Explanation :

First we have to calculate the charge of sodium ion.

q=ne

where,

q = charge of sodium ion

n = number of sodium ion = 2.68\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q=(2.68\times 10^{16})\times (1.6\times 10^{-19}C)=4.288\times 10^{-3}C

Now we have to calculate the charge of chlorine ion.

q'=ne

where,

q' = charge of chlorine ion

n = number of chlorine ion = 3.92\times 10^{16}

e = charge on electron = 1.6\times 10^{-19}C

Now put all the given values in the above formula, we get:

q'=(3.92\times 10^{16})\times (1.6\times 10^{-19}C)=6.272\times 10^{-3}C

Now we have to calculate the current passing between the electrodes.

I=\frac{q}{t}+\frac{q'}{t}

I=\frac{4.288\times 10^{-3}}{1.00}+\frac{6.272\times 10^{-3}}{1.00}

I=1.056\times 10^{-2}A

Thus, the current passing between the electrodes is, 1.056\times 10^{-2}A

4 0
3 years ago
What text features were used? font color, shadow, and bold font color, italics, and outline font color, italics, and bold font c
AlladinOne [14]

Answer:

Explanation:

question isnt clear

4 0
3 years ago
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