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Harrizon [31]
2 years ago
6

How does the chemistry of life relate to cellular respiration

Chemistry
1 answer:
storchak [24]2 years ago
3 0

Answer:

¿Cuál es la reaccion quimica de la respiracion celular?

La respiración celular es una reacción exergónica, donde parte de la energía contenida en las moléculas de alimento es utilizada por la célula para sintetizar ATP. ... Aproximadamente el 40% de la energía libre emitida por la oxidación de la glucosa se conserva en forma de ATP.

Explanation:

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andreyandreev [35.5K]
The greater the mass of an object, the greater<span> its gravitational force.
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6 0
3 years ago
Can someone help me?
kupik [55]

Answer:

#1)2.23hrs

Explanation:

= 134/60

=2.23

=2.23hrs

4 0
3 years ago
Examine the following equations.
Zigmanuir [339]

Answer:

A and B

Explanation:

This is because there was emission of gamma (Y) radiations in both the reactions.

8 0
3 years ago
how do you know the state of a compound when writing out the equation. WILL MARK BRAINLIEST PLEASE HELP!!
tester [92]

Answer:

The state of matter of each compound or molecule is indicated in subscript next to the compound by an abbreviation in parentheses. For example, a compound in the gas state would be indicated by (g), solid (s), liquid (l), and aqueous (aq).

Explanation:

3 0
3 years ago
sing any data you can find in the ALEKS Data resource, calculate the equilibrium constant K at 25.0°C for the following reaction
prisoha [69]

Answer:

2.76 × 10⁻¹¹  

Explanation:

I don’t have access to the ALEKS Data resource, so I used a different source. The number may be different from yours.

1. Calculate the free energy of formation of CCl₄

                         C(s)+ 2Cl₂(g)→ CCl₄(g)

ΔG°/ mol·L⁻¹:       0         0         -65.3

ΔᵣG° = ΔG°f(products) - ΔG°f(reactants) = -65.3 kJ·mol⁻¹

2. Calculate K

\text{The relationship between $\Delta G^{\circ}$ and K  is}\\\Delta G^{\circ} = -RT \ln K

T = (25.0 + 273.15) K = 298.15 K

\begin{array}{rcl}-65 300 & = & -8.314 \times 298.15 \ln K \\65300& = & 2479 \ln K\\26.34 & = & \ln K\\K& = & e^{26.34}\\&= & \mathbf{2.76 \times 10}^{\mathbf{11}}\\\end{array}

3 0
3 years ago
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