The magnitude of the net displacement is 95.3 m
Explanation:
To find the magnitude of the net displacement, we have to resolve each of the two displacements into the horizontal and vertical direction first.
1st displacement is:
at 
So its components are
2nd displacement is:
at 
So its components are
Therefore, the x- and y-components of the net displacement are:
Therefore, the magnitude of the final displacement is:
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Answer:
Mg will replace Ag in a compound
Explanation:
A single replacement reaction is driven by the position of ions on the activity series.
As a rule of thumb, the position of metal ions on the activity series determines their reactivity.
Metal ions that are above another are more reactive and they will displace those that are lower.
Generally, activity increases as we go up the group.
Mg ions are higher than Ag ions on the series so, Mg will displace Ag from a solution.
Answer:
592.92 x 10³ Pa
Explanation:
Mole of ammonia required = 10 g / 17 =0 .588 moles
We shall have to find pressure of .588 moles of ammonia at 30 degree having volume of 2.5 x 10⁻³ m³. We can calculate it as follows .
From the relation
PV = nRT
P x 2.5 x 10⁻³ = .588 x 8.32 x ( 273 + 30 )
P = 592.92 x 10³ Pa
To solve this problem it is necessary to apply the concepts related to Newton's second Law and the force of friction. According to Newton, the Force is defined as
F = ma
Where,
m= Mass
a = Acceleration
At the same time the frictional force can be defined as,
Where,
Frictional coefficient
N = Normal force (mass*gravity)
Our values are given as,
By condition of Balance the friction force must be equal to the total net force, that is to say
Re-arrange to find acceleration,
Therefore the acceleration the horse can give is 
The approximate speed of the sound wave traveling through the solid material is 1012m/s.
<h3>
Wavelength, Frequency and Speed</h3>
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
From the wavelength, frequency and speed relation,
λ = v ÷ f
Where λ is wavelength, v is velocity/speed and f is frequency.
Given the data in the question;
- Frequency of sound wave f = 440Hz = 440s⁻¹
- Wavelength of the wave λ = 2.3m
To determine the approximate speed of the wave, we substitute our given values into the expression above.
λ = v ÷ f
2.3m = v ÷ 440s⁻¹
v = 2.3m × 440s⁻¹
v = 1012ms⁻¹
v = 1012m/s
Therefore, the approximate speed of the sound wave traveling through the solid material is 1012m/s.
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