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Free_Kalibri [48]

3 years ago

9

if the Earth's core provides the heat that drives plate tectonics, then what will eventually happen as the Earth's core cools do

wn over billions of years?

1 answer:

Eduardwww [97]3 years ago

6 0

If the Earth's core cools down, then one of the first things that would happen is that plate tectonic activity would slow down. Over time, the Earth would then dry up into this ball of dry soil because the heat of the Earth's core drives water up to the surface. Since the crust would be void of majority of liquid, it would shrink by an unknown amount.

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Plzzzz help the question that are selected in the picture r not correct PLZZ help PLZZ give the answer I will mark u the brainli

lbvjy [14]

Answer:

D for the first one and A for the second.

Explanation:

Hurricanes are usually caused by warmer waters.

Wind is created due to the movement of air because of the temperatures.

3 0

3 years ago

The force on a dropped apple hitting the ground depends upon

yulyashka [42]

Answer:

F=ma

Explanation:

Force = mass * acceleration

5 0

3 years ago

What is the mass of a ball that has 29j of potential energy and is lifted 2.0m?

Salsk061 [2.6K]

Answer:

1.48kg

Explanation:

Here,

potential energy (P.E) = 29j

height (h) = 2m

acceleration due to gravity(g) =

$9.8m {s}^{ - 2}$

mass(m) = ?

we know,

P.E = mgh

or, 29 = m×9.8×2

or, 29/19.6 = m

or,m = 1.48kg

6 0

2 years ago

Choose the sentence that might be found in a personal narrative that correctly uses both a gerund and an infinitive.

Mumz [18]

Let's start with an infinitive: it has a form "to..." - only sentences C and D have a phrase like this, so we can exclude other options.

Among those, C does not have a gerund, which is a verbal form: "dreaming" has a function of a noun there.

So the correct answer is the remaining one, D.

3 0

3 years ago

A proton that has a mass m and is moving at 270 m/s in the i hat direction undergoes a head-on elastic collision with a stationa

Nataly_w [17]

Answer:

$V_p = 267.258 m/s$

$V_n = 38.375 m/s$

Explanation:

using the law of the conservation of the linear momentum:

$P_i = P_f$

where $P_i$ is the inicial momemtum and $P_f$ is the final momentum

the linear momentum is calculated by the next equation

P = MV

where M is the mass and V is the velocity.

so:

$P_i = m(270 m/s)$

$P_f = mV_P + M_nV_n$

where m is the mass of the proton and $V_p$ is the velocity of the proton after the collision, $M_n$ is the mass of the nucleus and $V_n$ is the velocity of the nucleus after the collision.

therefore, we can formulate the following equation:

m(270 m/s) = m $V_p$ + 14m $V_n$

then, m is cancelated and we have:

270 = $V_p$ + $14V_n$

This is a elastic collision, so the kinetic energy K is conservated. Then:

$K_i = \frac{1}{2}MV^2 = \frac{1}{2}m(270)^2$

and

Kf = $\frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2$

then,

$\frac{1}{2}m(270)^2$ = $\frac{1}{2}mV_p^2 +\frac{1}{2}(14m)V_n^2$

here we can cancel the m and get:

$\frac{1}{2}(270)^2$ = $\frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2$

now, we have two equations and two incognites:

270 = $V_p$ + $14V_n$ (eq. 1)

$\frac{1}{2}(270)^2$ = $\frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2$

in the second equation, we have:

36450 = $\frac{1}{2}V_p^2 +\frac{1}{2}(14)V_n^2$ (eq. 2)

from this last equation we solve for $V_n$ as:

$V_n = \sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }$

and replace in the other equation as:

270 = $V_p +$ 14 $\sqrt{\frac{36450-\frac{1}{2}V_p^2 }{\frac{1}{2} } }$

so,

$V_p = -267.258 m/s$

Vp is negative because the proton go in the -i hat direction.

Finally, replacing this value on eq. 1 we get:

$V_n = \frac{270+267.258}{14}$

$V_n = 38.375 m/s$

3 0

3 years ago