When the car starts moving it acquires kinetic energy.
For this problem the formula of kinetic energy is:
Where m is the mass of the car = 850kg, and v is the speed of the car.
If we consider insignificant the energy lost by friction with soil and air we can propose the following equation:
Applied energy = Kinetic energy acquired by the car.
The velocity is 5.531 m/s
Answer:
The proximate answer pertaining to your question entails 10 kg.
Justification:
The statement implies which of the following units preceded by the value of 10 will obtain substantial inertia.
Exploiting conversions, this can be evinced/demonstrated:
Choice "10 m" => .01 kg
10 J ==> 0.10
10 N ==> 1.02 kg
10 kg ==> 10 kg
Thus, an object obtaining a cumulative mass of 10 kg obtains substantial inertia.
<h3>*Hope this helps*</h3>
Answer:
1.02s
Explanation:
In this situation the following equation will be useful:

Where:
 is Marissa's car final velocity
 is Marissa's car initial velocity
 is Marissa's car constant acceleration (assuming this is the acceleration, since 1269 m/s^{2} does not make sense)
 is the time it takes to accelerato from  to 
Answer:
In the grapher: The stops are marked with a flat line, velocity with a diagonal line, and acceleration with a curve.
Average speed= Total distance/Total time
Explanation:
