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2 years ago

Explain the molecular concept of thermal energy.

Physics

1 answer:

MAVERICK [17]2 years ago

7 0

Answer:

The temperature of an object increases when the molecules that make up that object move faster. Thermal energy is energy possessed by an object or system due to the movement of particles within the object or the system.

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The counter is 1.5 m high, and the bowl has a mass of 0.5 kg. How much gravitational energy is stored in the bowl-earth system?

alina1380 [7]

Answer:

7.35 J

Im assuming, upon answering the question, that the gravity in this scenario is 9.8? As 9.8 is the gravitational force upon the earth.

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2 years ago

You ran a power plant what could you do to make this generator produce electricity

DIA [1.3K]

You could use a magnetic generator or you could use hydraulic power

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2 years ago

The current in a 100-w bulb connected to a 120-v source is

ivolga24 [154]

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2 years ago

An investigator collects a sample of a radioactive isotope with an activity of 490,000 Bq.48 hours later, the activity is 110,00

Daniel [21]

Answer:

The correct answer is "22.27 hours".

Explanation:

Given that:

Radioactive isotope activity,

= 490,000 Bq

Activity,

= 110,000 Bq

Time,

= 48 hours

As we know,

⇒ $A = A_0 e^{- \lambda t}$

or,

⇒ $\frac{A}{A_0}=e^{-\lambda t}$

By taking "ln", we get

⇒ $ln \frac{A}{A_0}=- \lambda t$

By substituting the values, we get

⇒ $-ln \frac{110000}{490000} = -48 \lambda$

⇒ $-1.4939=-48 \lambda$

$\lambda = 0.031122$

As,

⇒ $\lambda = \frac{ln_2}{\frac{T}{2} }$

then,

⇒ $\frac{ln_2}{T_ \frac{1}{2} } =0.031122$

⇒ $T_\frac{1}{2}=\frac{ln_2}{0.031122}$

$=22.27 \ hours$

3 0

2 years ago

Two objects are dropped from rest from the same height. Object A falls through a distance during a time t, and object B falls th

UNO [17]

Answer:

Distance covered by B is 4 times distance covered by A

Explanation:

For an object in free fall starting from rest, the distance covered by the object in a time t is

$s=\frac{1}{2}gt^2$

where

s is the distance covered

g is the acceleration due to gravity

t is the time elapsed

In this problem:

- Object A falls through a distance $s_A$ during a time t, so the distance covered by object A is

$s_A=\frac{1}{2}gt^2$

- Object B falls through a distance $s_B$ during a time 2t, so the distance covered by object B is

$s_B=\frac{1}{2}g(2t)^2 = 4(\frac{1}{2}gt^2)=4s_A$

So, the distance covered by object B is 4 times the distance covered by object A.

5 0

2 years ago