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postnew [5]
3 years ago
14

A radio wave has a speed of 3.00 x10^8 and a frequency of 100 MHz. What is the wavelength?

Physics
1 answer:
dlinn [17]3 years ago
5 0

Answer:

Wavelength of radio is wave is 3 m

Explanation:

Wavelength of radio is wave is

\lambda=\frac{v}{f}

where

v=3 \times 10^8 m\s\\f=100 Mhz

wavelength is

\lambda=\frac{3\times 10^8}{100\times 10^6} \\\\\lambda=3 m\\

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an atom is chemically stable when its outer layer is completely filled with energy. im pretty sure this is right

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In which type of bone does ossification occur in the membranes?
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In the formation of flat bones such as the skull the mandibles and the clavicles  
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3 years ago
A spring is 20cm long is stretched to 25cm by a load of 50N. What will be its length when stretched by 100N. assuming that the e
IgorLugansk [536]

Answer:

Final Length = 30 cm

Explanation:

The relationship between the force applied on a string and its stretching length, within the elastic limit, is given by Hooke's Law:

F = kΔx

where,

F = Force applied

k = spring constant

Δx = change in length of spring

First, we find the spring constant of the spring. For this purpose, we have the following data:

F = 50 N

Δx = change in length = 25 cm  - 20 cm = 5 cm = 0.05 m

Therefore,

50 N = k(0.05 m)

k = 50 N/0.05 m

k = 1000 N/m

Now, we find the change in its length for F = 100 N:

100 N = (1000 N/m)Δx

Δx = (100 N)/(1000 N/m)

Δx = 0.1 m = 10 cm

but,

Δx = Final Length - Initial Length

10 cm = Final Length - 20 cm

Final Length = 10 cm + 20 cm

<u>Final Length = 30 cm</u>

6 0
3 years ago
These three bulbs are powered by the battery. What will happen if the middle light burns out? A. The two other bulbs will go out
Anna11 [10]

Answer:

C

Explanation:

4 0
3 years ago
A 42.0-kg parachutist is moving straight downward with a speed of 3.85 m/s. (a) If the parachutist comes to rest with constant a
RideAnS [48]

Answer:

-414.96 N

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-3.85^2}{2\times 0.75}\\\Rightarrow a=-9.88\ m/s^2

F=ma\\\Rightarrow F=42\times -9.88\\\Rightarrow F=-414.96\ N

The force the ground exerts on the parachutist is -414.96 N

If the distance is shorter than 0.75 m then the acceleration will increase causing the force to increase

5 0
3 years ago
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