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Varvara68 [4.7K]
3 years ago
15

This is a real math problem

Mathematics
1 answer:
Elden [556K]3 years ago
7 0

Gimme a minute to calculate it.

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Find the 25th of sequence 3,5,7,9,11
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Answer: The 25th term of the sequence is 75

Step-by-step explanation:

The given sequence depicts an arithmetic progression. The consecutive terms differ by a common difference. We will apply the formula for arithmetic progression.

Tn = a + (n-1)d

Tn = The value of the nth term of the arithmetic sequence.

a = first term of the sequence.

d = common difference (difference between a term and the consecutive term behind it)

n = number of terms in the sequence.

From the information given,

a = 3

d = 5-3 = 7-5 = 2

We want to look for the 25th term, T25

So n = 25

T25 = 3 + (25-1)2 = 3+ 24×2

T25 = 3 + 72 = 75

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Simplify 3^8 ÷ 3^2 <br> A. 3^4<br> B. 3^10<br> C. 3^6<br> D. 3^6
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When dividing two squares, you minus the number

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