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cricket20 [7]
2 years ago
5

C3H8+3O2 = 3CO2+4H2O what is the enthalpy combustion please show work

Chemistry
1 answer:
irakobra [83]2 years ago
5 0

Answer:

\Delta H_{comb}=2043.85kJ/mol

Explanation:

Hello there!

In this case, according to the given chemical reaction, it possible for us to set up the expression for the calculation of the enthalpy change as shown below:

\Delta H_r=-\Delta H_{comb}=3\Delta _fH_{CO_2}+4\Delta _fH_{H_2O}-\Delta _fH_{C_3H_8}-3\Delta _fH_{O_2}

Thus, given the values of the enthalpies of formation on the attached file, we obtain:-\Delta H_{comb}=3(-393.5kJ/mol)+4(-241.8kJ/mol)-(-103.85kJ/mol)-3(0kJ/mol)\\\\-\Delta H_{comb}=-2043.85kJ/mol\\\\\Delta H_{comb}=2043.85kJ/mol

Best regards!

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Answer: Here are the answers

Explanation:

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3 years ago
Using Raoult’s law, estimate the boiling pressure and mole fractions in the vapor phase that is in equilibrium with a liquid hav
fenix001 [56]

Answer:

a) boiling pressure:

P = 0.759 atm

b) mole fractions in the vapor phase:

Xethanol(v) = 0.2192

Xwater(v) = 0.7808

Explanation:

Raoult's law:

  • Pa = (P*a)×(Xa,(l))
  • Xa(l) + Xb(l) = 1

∴ a: water

∴ b: ethanol

∴ Xb(l) = 0.1238

⇒ Xa(l) = 1 - 0.1238 = 0.8762

  • Pt = Pa + Pb

vapor pressure of the pure components at T = 85.3°C:

∴ P*a(85.3°C) ≅ 400 torr (0.53 atm).....from literature

∴ P*b(85.3°C) ≅ 800 torr (1.053 atm).....from literature

total pressure of the mix:

⇒ Pt = ((0.53 atm)(0.8762)) + ((1.053 atm)(0.1238))

⇒ Pt = 0.5947 atm

boiling point:

  • Xb(l) = Xa(l) = 0.5
  • P = (P*b - Pt)(0.5) + P*a

⇒ P = ((1.053 atm - 0.5947 atm)(0.5)) + 0.53 atm

⇒ P = 0.759 atm

assuming that the gas system is ideal:

  • (Xb(v))(Pt) = (P*b)(Xb(l))

fraction in the vapor fase, ethanol:

⇒ Xb(v) = (P*b)(Xb(l)) / Pt

⇒ Xb(v) = ((1.053 atm)(0.1238)) / (0.5947 atm)

⇒ Xb(v) = 0.2192

∴ Xa(v) = 1 - Xb(v)

⇒ Xa(v) = 1 - 0.2192 = 0.7808

3 0
2 years ago
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Montano1993 [528]

Answer:

C

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The region of space outside the system is called the surroundings. Hence everything outside the cup constitutes the surroundings.

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PIT_PIT [208]

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\pi =CRT

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Naddik [55]

Answer:

B

Explanation:

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4 0
2 years ago
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