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3 years ago

In a classical long run supply model the economy is always doing what

Chemistry

1 answer:

ch4aika [34]3 years ago

8 0

Answer:

Economy is always at the full employment level of output

Explanation:

The economy in a classical long-run supply model will always have the same economic output

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What is the energy change when 78.0 g of Hg melt at −38.8°C

adell [148]

Answer:

The correct answer is - 2.557 KJ

Explanation:

In this case, Hg is melting, the process is endothermic, so the energy change will have a positive sign.

we can calculate this energy by the following formula:

Q = met

where, m = mass,

e = specific heat

t = temperature

then,

Q = 78*0.14* (273-38.8)

here 0.14 = C(Hg)

= 2.557 Kj

5 0

2 years ago

What element is CU?plz helpppp

Ulleksa [173]

CU is the element symbol for Copper.

8 0

3 years ago

Read 2 more answers

Read the picture :) please and thank you!

lana [24]

It's "C" a sample of dust particles at 0 Pascals

5 0

3 years ago

Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such

8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

1 A = 1 C/s
The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

$19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g$

5 0

3 years ago

A chemistry student needs 50.0 g of methyl acetate for an experiment. By consulting the CRC Handbook of Chemistry and Physics, t

slamgirl [31]

Explanation:

As density is defined as the mass of a substance divided by its volume.

Mathematically, Density = $\frac{mass}{volume}$

It is given that mass is 50 g and density is 0.934 $g/cm^{3}$ .

Hence, calculate the volume of methyl acetate as follows.

Density = $\frac{mass}{volume}$

0.934 $g/cm^{3}$ = $\frac{50 g}{volume}$

Volume = $53.53 cm^{3}$

or, = $53.53 ml$ (as 1 $cm^{3}$ = 1 mL)

Thus, we can conclude that the volume of methyl acetate the student should pour out is $53.53 ml$ .

3 0

3 years ago