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maw [93]
3 years ago
8

Determine the values of mm and nn when the following mass of the Earth is written in scientific notation: 5,970,000,000,000,000,

000,000,000 kgkg.
Physics
1 answer:
nataly862011 [7]3 years ago
5 0

Answer:

"m" and "n" are 5.97 and 24 respectively.

Explanation:

Standard form which is a scientific notation [m × 10^n] can be regarded as way to reduce large figures to small one in a decimal firm and this is usually done for conviniency sake.

✓Let us find "m" , to do this we will shorten the long number so that it will be from 1-9. And this is 5.97, hence

m = 5.97

✓ " n" can be determined by counting the digits from our right hand then stop where the decimal point was put when we were finding our "m". Hence

n= 24

✓ if we input the values to the scientific expresion above, we have

m = 5.97 and n = 24

Hence, the Standard form = 5.97 × 10^24 kg which is the scientific notation.

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Digiron [165]

To solve this problem we will apply the concepts related to the conservation of momentum. By definition we know that the initial moment must be equivalent to the final moment of the two objects therefore

p_1 = p_2

m_1u_1+m_2u_2 = m_1v_1+ m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

v_{1,2}= Final velocity of each object

Since the initial velocity relative to the metal tank is at rest, that velocity will be zero. And considering that in the end, the speed of the two bodies is the same, the equation would become

m_1u_1 = (m_1+m_2)v_f

Rearranging to find the velocity,

v_f = \frac{m_1u_1}{ (m_1+m_2)}

Replacing we have that,

v_f = \frac{(332)(2.3)}{ (332+19.5)}

v_f = 2.17 m/s

Therefore the velocity of the shark immediately after it swallows the tank is 2.17m/s

4 0
3 years ago
I need answer fast please
Hatshy [7]

gold density = 38.6 *10^-3 / 2 *10^-6 = 19300 Kg/m3 Iron density = 46.8 *10^-3 / 6 *10^-6 = 7800 Kg/m3 water mass = density*volume = 1 * 10 = 10 grams = 0.01 Kg

4 0
3 years ago
given that the 180N weight causes a total extension of 30cm ,determine the spring constant of each spring (the weight of each sp
IrinaK [193]

Answer:600N/m

Explanation:  Given ;

                       Applied force(F) = 180N

                      Total extension (l) = 30cm =0.30m

                       Spring constant(K) =?

                       From Hooke's law

                         F= kx

                        therefore k= F/x

                                  k = 180N/0.3m

                                    600N/m  

8 0
3 years ago
A 1550 kg car located at < 319, 0, 0 > m has a momentum of < 45000, 0, 0 > kg·m/s. What is its location 10 s later?
Serggg [28]

Answer:

< 45319, 0, 0 > m

Explanation:

mass, m = 1550 kg

r = < 319, 0, 0 > m

v = < 4500, 0, 0 > m/s

t = 10 s

distance traveled in 10 second is

d =  v x t

d = < 4500 x 10, 0 x 10, 0 x 10 > m

d = < 45000, 0, 0 > m

So, the new location of the car is

r' = r + d = < 319, 0, 0 > + < 45000, 0, 0 >

r' = < 45319, 0, 0 > m

5 0
3 years ago
If an object accelerates from rest, with a constant acceleration of 6.4 m/s2, what will
adell [148]

Answer:

120 m/s

Explanation:

Acceleration = 6.4 m/s²

Initial velocity = 0 m/s

Time = 18 s

v = at + v₀

v = (6.4)(18) + 0

v = 115.2

Rounded to two significant figures, the final velocity is 120 m/s.

3 0
3 years ago
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