Answer:
a) Mo the electron configuration: 42Mo: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d4
Mo3+ - is Paramagnetic
b) Au - [Xe] 4f14 5d10 6s1
For Au+ is not paramagnetic
c) Mn - [Ar] 3d5 4s2
Mn2+ is paramagnetic
d)Hf -[Xe] 4f¹⁴ 5d² 6s²
Hf2+ is not paramagnetic
Explanation:
An atom becomes positively charged when it looses an electron.
Diamagnetism in atom occurs whenever two electrons in an orbital paired equalises with a total spin of 0.
Paramagnetism in atom occurs whenever at least one orbital of an atom has a net spin of electron. That is a paramagnetic electron is just an unpaired electron in the atom.
Here is a twist even if an atom have ten diamagnetic electrons, the presence of at least one paramagnetic electron, makes it to be considered as a paramagnetic atom.
Simply put paramagnetic elements are one that have unpaired electrons, whereas diamagnetic elements do have paired electron.
From what there’s nothing there? :)
Answer:
C8H18(g) + 12.5O2(g) -> __8__CO2(g) + 9H2O(g) + heat
CH4(g) + _2___O2(g) -> ____CO2(g) + _2___H2O(g) + heat
C3H8(g) + _5___O2(g) -> _3___CO2(g) + __4__H2O(g) + heat
2C6H6(g) + __15__O2(g) -> __12__CO2(g) + __6__H2O(g) + heat
Explanation:
I hope it helps!
