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Crazy boy [7]
3 years ago
6

¿Que piensas respecto al hecho de que María y Efraín rara vez se comunican directamente?

Engineering
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

Crean un código usando la naturaleza.

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A handsfree device may be used if it can be activated or deactivate with a?
NeX [460]

A handsfree device may be used if it can be activated or deactivate with a cellphone.

<h3>What is hands-free?</h3>

Handsfree is a device which when connected to a cell device can be used in listening to audio, video and messages.

A driver can also activate or deactivate with a swipe when connect to the vehicle audio device.

Therefore,

A handsfree device may be used if it can be activated or deactivate with a cellphone.

Learn more on handsfree below

brainly.com/question/12253610

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7 0
2 years ago
Please what is the name of this tool​
madam [21]

Answer: it’s called a saw or see saw

Explanation: it works by cutting a tree, wood, tile, etc.

5 0
3 years ago
Read 2 more answers
The flowrate through a rectangular channel is 20 cfs. The upstream width of the channel is 10 ft, and the depth of the water in
Liula [17]

To solve this problem we will use the Froude number that relates the Forces of Inertia with the Forces of Gravity. There will be jump in the downstream only if Froude Number (Fr) is greater than 1 at upstream. Our values are given as,

Q = 20cfs\\w= 10ft\\D= 1ft

Then the velocity would be:

V = \frac{Q}{wD}V = \frac{20}{10*1}V = 2ft/s

The number of Froude is given as,

Fr = \frac{V}{gD}^{1/2}

Where,

V = Velocity

g = Gravity

D = Diameter

Replacing we have that

Fr = \frac{2}{32.2}^{1/2}\\Fr = 0.352\\Fr

There will be no Jump, correct answer is B.

5 0
3 years ago
What is the acceleration of a car that has a velocity of 20 m/s, and
ella [17]

Acceleration of Car = 10 ms⁻²

Explanation:

Step 1:

The basic formula of acceleration is a = (v-u)/t  ms⁻²

where, v- final velocity

            u- initial velocity

             t= time taken

Step 2:

Here v = 70 ms⁻¹

        u = 50  ms⁻¹

         t = 5 s

∴ a = ( 70 - 20)/5

a = 10 ms⁻²

7 0
4 years ago
It is safe to keep a cylinder next to the actual welding or cutting operation, true or false?
Alinara [238K]

Answer:

Explanation:

Cylinders shall be kept far enough away from the actual welding or cutting operation so that sparks, hot s lag, or flame will not reach them. When this is impractical, fire resistant shields shall be provided. Cylinders shall be placed where they cannot become part of an electrical circuit.

7 0
3 years ago
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