Answer:
Option B
1025 psi
Explanation:
In a single shear, the shear area is
The shear strength=
and in this case
Shear strength=
hence making load the subject then
Load=Shear area X Shear strength
Load=
Answer:
P=361.91 KN
Explanation:
given data:
brackets and head of the screw are made of material with T_fail=120 Mpa
safety factor is F.S=2.5
maximum value of force P=??
<em>solution:</em>
to find the shear stress
T_allow=T_fail/F.S
=120 Mpa/2.5
=48 Mpa
we know that,
V=P
<u>Area for shear head:</u>
A(head)=π×d×t
=π×0.04×0.075
=0.003×πm^2
<u>Area for plate:</u>
A(plate)=π×d×t
=π×0.08×0.03
=0.0024×πm^2
now we have to find shear stress for both head and plate
<u>For head:</u>
T_allow=V/A(head)
48 Mpa=P/0.003×π ..(V=P)
P =48 Mpa×0.003×π
=452.16 KN
<u>For plate:</u>
T_allow=V/A(plate)
48 Mpa=P/0.0024×π ..(V=P)
P =48 Mpa×0.0024×π
=361.91 KN
the boundary load is obtained as the minimum value of force P for all three cases. so the solution is
P=361.91 KN
note:
find the attached pic
Answer:You are a network engineer. While moving a handheld wireless LAN device, you notice that the signal strength increases when the device is moved from a ...
Explanation:
Answer:
Explanation:
A confined aquifer is one that's impermeable and does not allow seepage's of water through it.
An unconfined aquifer is a body of water that has permeable membranes which allows passage of water through it.
There will be little or no transmission of water trough these bodies of water.
Answer:
see explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
The attached files has the solved problem.