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2 years ago

Based on the given reactants, what type of chemical reaction will take place? Zn + 02 -

Chemistry

1 answer:

Marianna [84]2 years ago

4 0

Answer:Classify each of the following chemical reactions.

S + O2 → SO2

CaCl2 + 2AgNO3 → Ca(NO3)2 + 2AgCl

Zn + CuSO4 → Cu + ZnSO4

2Na2O → 4Na + O

Explanation:

synthesis and combustion

double replacement

single replacement

decomposition only

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HCl(?) + H2O(?) → H3O+(?) + Cl-(?)

larisa86 [58]

Answer:

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2 years ago

Please fast but right no link or bot

Aneli [31]

Answer:

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Explanation:

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1 year ago

Read 2 more answers

How many grams of aluminum can react with 336g oxygen? 4Al + 3O2 --> 2Al2O3

baherus [9]

Answer: 714 g Al2O3

Explanation: Solution attached

First convert mass of O2 to moles

Do the mole ratio between O2 and Al2O3 from the balanced equation.

Convert moles of Al2O3 to mass using its molar mass.

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2 years ago

At a certain temperature, the solubility of strontium arsenate, Sr3(AsO4)2, is 0.0540 g/L. What is the Ksp of this salt at this

blondinia [14]

<span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles

Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq)

Ksp = (Sr++)^3(As04^-3)^2

(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4

(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4

<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th

I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span></span>

7 0

2 years ago

You have 345 mL of a 2.5 M NaCl solution. If you boil the water until the volume of the solution is 250 mLwhat will the molarity

HACTEHA [7]

The molarity of the solution will be 3.45 M

<h3>Further explanation </h3>

Dilution is the process of adding a solvent to get a more dilute solution.

The moles(n) before and after dilution are the same.

Can be formulated :

M₁V₁=M₂V₂

M₁ = Molarity of the solution before dilution

V₁ = volume of the solution before dilution

M₂ = Molarity of the solution after dilution

V₂ = Molarity volume of the solution after dilution

The initial solution

345 mL of a 2.5 M NaCl solution.

M₁=2.5 M

V₁=345 ml

The solution after boiled :

V₂=250 ml

$\tt M_2=\dfrac{M_1.V_1}{V_2}\\\\M_2=\dfrac{2.5\times 345}{250}\\\\M_2=3.45~M$

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2 years ago