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3 years ago

BRAINLIEST IF CORRECT

Chemistry

2 answers:

PSYCHO15rus [73]3 years ago

6 0

Answer:

D) All Of The Above

Explanation:

There are five main modes of seed dispersal: gravity, wind, ballistic, water, and by animals.

Some plants are serotinous and only disperse their seeds in response to an environmental stimulus.

MARK THIS ANSWER AS THE BRAINLIEST PLEASE ❤️

krek1111 [17]3 years ago

3 0

Answer : not sure but I think that’s it’s D .

You might be interested in

If you push on a wall with 200n with what forth with the wall push back

sweet-ann [11.9K]

According to newtons law every action has a equal reaction therefore it will push back 200n aswell

4 0

3 years ago

The weight of a sack potato in india is 50kgf. will the weight increase or decrease in bhutan. why

AfilCa [17]

Answer:

Assume that the sack was initially close to the sea level. Its weight will increase even though its mass stays the same.

Explanation:

The weight of an object typically refers to the size of the planet's gravitational attraction (a force) on this object. That's not the same as the mass of the object. The weight of an object at a position depends on the size of the gravitational field there; on the other hand, the mass of the object is supposed to be same regardless of the location- as long as the object stays intact.

Let $g$ denote the strength of the gravitational field at a certain point. If the mass of an object is $m$ , its weight at that point will be $m \cdot g$ .

Indeed, $g \approx 9.81\; \rm N \cdot kg^{-1}$ on many places of the earth. However, this value is accurate only near the sea level. The equation for universal gravitation is a more general way for finding the strength of the gravitational field at an arbitrary height. Let $G$ denote the constant of universal gravitation, and let $M$ denote the mass of the earth. At a distance $r$ from the center of the earth (where

$\displaystyle g \approx \frac{G \cdot M}{r^2}$ .

The elevation of many places in Bhutan are significantly higher than that of many places in India. Therefore, a sack of potato in Bhutan will likely be further away from the center of the earth (larger $r$ ) compared to a sack of potato in India.

Note, that in the approximation, the value of $g$ is (approximately, because the earth isn't perfectly spherical) inversely proportional to the distance from the center of the planet. The gravitational field strength

On the other hand, the weight of an object of fixed mass is proportional to the gravitational field strength. Therefore, the same bag of potatoes will have a smaller weight at most places in Bhutan compared to most places in India.

6 0

3 years ago

11. What is the specific heat of a substance with a mass of 25.5 g that requires 412 J

Romashka-Z-Leto [24]

Answer:

297 J

Explanation:

The key to this problem lies with aluminium's specific heat, which as you know tells you how much heat is needed in order to increase the temperature of

1 g

of a given substance by

∘

In your case, aluminium is said to have a specific heat of

0.90

∘

So, what does that tell you?

In order to increase the temperature of

1 g

of aluminium by

∘

, you need to provide it with

0.90 J

of heat.

But remember, this is how much you need to provide for every gram of aluminium in order to increase its temperature by

∘

. So if you wanted to increase the temperature of

10.0 g

of aluminium by

∘

, you'd have to provide it with

1 gram



0.90 J

1 gram



0.90 J

...

1 gram



0.90 J



10 times

0.90 J

However, you don't want to increase the temperature of the sample by

∘

, you want to increase it by

∘

−

∘

This means that you're going to have to use that much heat for every degree Celsius you want the temperature to change. You can thus say that

∘



0.90 J

∘



0.90 J

...

∘



0.90 J



33 times

0.90 J

Therefore, the total amount of heat needed to increase the temperature of

10.0 g

of aluminium by

∘

will be

10.0

⋅

0.90

∘

⋅

∘

297 J

I'll leave the answer rounded to three sig figs, despite the fact that your values only justify two sig figs.

For future reference, this equation will come in handy

⋅

, where

- the amount of heat added / removed

- the mass of the substance

- the specific heat of the substance

- the change in temperature, defined as the difference between the final temperature and the initial temperature of the sample

6 0

4 years ago

Both protons and neutrons (and their anti-particles) froze out:

VladimirAG [237]

I think Both protons and neutrons (and their anti-particles) froze out at 1013 K, about 0.0001 seconds after the Big Bang. Protons and neutrons are sub atomic particles of an atom that are found in the nucleus of an atom. Proton is the positively charge particle while the neutron has no charge. The proton positive charge accounts for the positive nuclear charge.

6 0

4 years ago

Help pls I will mark brainlest

defon

Resources found in lithosphere: gold and iron etc

Resources found in atmosphere: Water vapor, gases etc.

4 0

3 years ago