Answer:
Kc = 9.52.
Explanation:
<em>A + 2B ⇌ C,</em>
Kc = [C]/[A][B]²,
Concentration: [A] [B] [C]
At start: 0.3 M 1.05 M 0.55 M
At equilibrium: 0.3 - x 1.05 - 2x 0.55 + x
0.14 M 1.05 - 2x 0.71 M
- For the concentration of [A]:
∵ 0.3 M - x = 0.14 M.
∴ x = 0.3 M - 0.14 M = 0.16 M.
∴ [B] at equilibrium = 1.05 - 2x = 1.05 M -2(0.16) = 0.73 M.
<em>∵ Kc = [C]/[A][B]²</em>
∴ Kc = (0.71)/(0.14)(0.73)² = 9.5166 ≅ 9.52.
The answer will be:
Solubility of the mixture = 21.5/60 x 25 = 8.96
Hope this helps.
Answer:
The answer to your question is 150 ml
Explanation:
Data
Volume 1 = 25 ml
Concentration 1 = 0.6 M
Volume 2 = ?
Concentration 2 = 0.1 M
Formula
Volume 1 x Concentration 1 = Volume 2 x Concentration 2
Solve for Volume 2
Volume 2 = (Volume 1 x Concentration 1)/Concentration 2
Substitution
Volume 2 = (25 x 0.6) / 0.1
Simplification
Volume 2 = 15 / 0.1
Result
Volume 2 = 150 ml